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kipiarov [429]
3 years ago
10

if the density of a bar of gold is 19.3g/cm^3and you cut it into four pieces , what is its density of each piece of gold

Chemistry
1 answer:
AlladinOne [14]3 years ago
4 0
Density is an intrinsic property, so it is independent of the amount of substance present: one gold coin would have the same density as a solid gold boulder.

So if the density of gold is 19.3 g/cm³, the density of a bar of gold and the pieces into which the bar is cut would all be 19.3 g/cm³.
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M(A₂O₃)=101.96 g/mol
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8 0
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Why is hydronium ion not an electrophile
galina1969 [7]

Answer:

Hydronium ion is not an electrophile because, its positive charge is on oxygen and its octet is filled.

Explanation:

5 0
2 years ago
PLEASE HELP ME!! DIMENSIONAL ANALYSIS<br> CHEMISTRY<br> DUE IN 5 MINS!!!
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Answer:

12 mi/h

Explanation:

Step 1: Given data

  • Total distance (d): 6 km
  • Time elapsed (t): 19 min

Step 2: Convert "d" to miles

We will use the conversion factor 1 mi = 1.60934 km.

6 km × 1 mi/1.60934 km = 3.7 mi

Step 3: Convert "t" to hours

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Step 4: Calculate the average speed of the runner (s)

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6 0
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Which will cause the value of the equilibrium constant to change? (2 points)
Sonbull [250]

answer

changing the temperature and increase in the pressure

Change in concentration, pressure, catalyst, inert gas addition, etc. have  no effect on concentration, pressure, catalyst, inert gas addition lead to a shift in equilibrium position .

4 0
2 years ago
Read 2 more answers
A 35.40 gram hydrate of sodium carbonate, Na2CO3•nH2O, is heated to a constant mass. Its final weight is 30.2 g. What is formula
Sever21 [200]

Answer:

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Explanation:

After it is heated, the remaining mass is the mass of sodium carbonate.

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Mass is conserved, so the difference is the mass of the water:

35.4 g − 30.2 g = 5.2 g H₂O

Convert masses to moles:

30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃

5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O

Normalize by dividing by the smallest:

0.285 / 0.285 = 1.00 mol Na₂CO₃

0.289 / 0.285 = 1.01 mol H₂O

The ratio is approximately 1:1.  So the formula of the hydrate is Na₂CO₃•H₂O.

3 0
3 years ago
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