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3 years ago

How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 88.1 molesmoles of water vapor?

Chemistry

1 answer:

irga5000 [103]3 years ago

8 0

Answer:

88.1 moles of H₂

Explanation:

Let's make the reaction:

H₂(g) + CO₂(g) → H₂O(g) + CO(g)

Ratio is 1:1

Therefore, 1 mol of hydrogen reacts with 1 mol of carbon dioxide to produce 1 mol of water and 1 mol of carbon monoxide.

In conclusion, 88.1 moles of water must be produced by 88.1 moles of H₂

The reaction can also be written as an equilbrium

H₂(g) + CO₂(g) ⇄ H₂O(g) + CO(g) Kc

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The highly reactive elements in group 7A are known for forming salts. What are they called? transition metals metalloids halogen

liberstina [14]

The group 7A elements are called Halogens.

Please mark as brainliest if this helped! :)

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2 years ago

Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu

pochemuha

Answer : The volume of $CO_2$ will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

$HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2$

First we have to calculate the mass of $HCO_3^-$ in tablet.

$\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g$

Now we have to calculate the moles of $HCO_3^-$ .

Molar mass of $HCO_3^-$ = 1 + 12 + 3(16) = 61 g/mole

$\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles$

Now we have to calculate the moles of $CO_2$ .

From the balanced chemical reaction, we conclude that

As, 1 mole of $HCO_3^-$ react to give 1 mole of $CO_2$

So, 0.0202 mole of $HCO_3^-$ react to give 0.0202 mole of $CO_2$

The moles of $CO_2$ = 0.0202 mole

Now we have to calculate the volume of $CO_2$ by using ideal gas equation.

$PV=nRT$

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = $37^oC=273+37=310K$

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

$(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)$

$V=0.51411L=514.11ml$

Therefore, the volume of $CO_2$ will be, 514.11 ml

6 0

2 years ago

List 2 things that about Velocity and Speed that are Different and two that are the same.

frozen [14]

Hey there!
Speed and velocity both:
1) Measure how fast something is moving
2) Both measured in miles per hour, meters/second, etc (rates)
However, there's a prime difference:
Different because:
1) Velocity is speed, but in a certain direction
2) Velocity is a vector
3) Velocity can be positive <em>or</em> negative, unlike speed.
I added another just in case you had a preference :)

Hope this helps!

8 0

3 years ago

One mole of carbon will have the same number of particles as one mole of hydrogen.

AVprozaik [17]

And the answer is False,it does not have the same number with particles as the one mole of hydrogen.

3 0

3 years ago

Read 2 more answers

When electrodes are used to record the electrocardiogram, an electrolyte gel is usually put between them and the surface of the

klemol [59]

Answer:

The equivalent circuit for the electrode while the electrolyte gel is fresh

From the uploaded diagram the part A is the electrolyte, the part part B is the electrolyte gel when is fresh and the part C is the surface of the skin

Now as the electrolyte gel start to dry out the resistance $R_s$ of the gel begins to increase and this starts to limit the flow of current . Now when the gel is then completely dried out the resistance of the gel $R_s$ then increases to infinity and this in turn cut off flow of current.

The diagram illustrating this is shown on the second uploaded image

Explanation:

5 0

2 years ago