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mixas84 [53]
3 years ago
11

How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 88.1 molesmoles of water vapor?

Chemistry
1 answer:
irga5000 [103]3 years ago
8 0

Answer:

88.1 moles of H₂

Explanation:

Let's make the reaction:

H₂(g) + CO₂(g) → H₂O(g) + CO(g)

Ratio is 1:1

Therefore, 1 mol of hydrogen reacts with 1 mol of carbon dioxide to produce 1 mol of water and 1 mol of carbon monoxide.

In conclusion, 88.1 moles of water must be produced by 88.1 moles of H₂

The reaction can also be written as an equilbrium

H₂(g) + CO₂(g) ⇄ H₂O(g) + CO(g)           Kc

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A solution of 0.0027 M K2CrO4 was diluted from 3.00 mL to 100. mL. What is the molarity of the new solution?
Stells [14]

Answer:

[K₂CrO₄] → 8.1×10⁻⁵ M

Explanation:

First of all, you may know that if you dilute, molarity must decrease.

In the first solution we need to calculate the mmoles:

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mL . M = mmol

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These mmoles  of potassium chromate are in 3 mL but, it stays in 100 mL too.

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0.0081 mmoles / 100mL = 8.1×10⁻⁵ M

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3 years ago
Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
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Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

 moles HCl = moles KOH \\  \\ cHCl*vHCl=cKOH*vKOH \\  \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}=  541,54mL

So, the required volume of HCl is 541,54 mL

Have a nice day!
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