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bagirrra123 [75]
3 years ago
15

Activity C: Hydrolysis of Carbohydrates As discussed earlier, disaccharides are composed of two monosaccharides linked together.

Polysaccharides are long chains of monosaccharides. The bonds joining these subunits can be broken in a process called hydrolysis. In this procedure, you will hydrolyze sucrose and starch by heating them with acid. What monosaccharides will result from the hydrolysis of sucrose? What monosaccharide will result from the hydrolysis of starch? The hydrolysis reactions will be carried out in two large test tubes. As Figure 3 shows, one contains sucrose and hydrochloric acid (HCI) and the
Chemistry
1 answer:
adelina 88 [10]3 years ago
4 0

Answer:

Sucrose: glucose and fructose

Explanation:

<em>What monosaccharides will result from the hydrolysis of sucrose?</em>

<em>Sucrose</em> is a <em>disaccharide</em> composed of 2 different <em>monosaccharides</em>: glucose and fructose joining by a 1 ⇒ 2 bond. These monosaccharides will be released upon the hydrolysis of sucrose.

<em>What monosaccharide will result from the hydrolysis of starch?</em>

<em>Starch</em> is a <em>polysaccharide</em> composed of numerous glucose monomers joined by glycosidic bonds (1 ⇒ 4 and 1 ⇒ 6). These monosaccharides will be released upon the hydrolysis of starch.

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Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce
Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol

According to the reaction shown below:-

MgCO_3\rightarrow MgO+CO_2

CaCO_3\rightarrow CaO+CO_2

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = \frac{x}{84.3139}\ mol

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = \frac{x}{84.3139}\times 40.3044 \ g

Moles of CaO = \frac{9.66 - x}{100.0869}\ mol

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = \frac{9.66 - x}{100.0869}\times 56.0774 \ g

Given that total mass of the oxide = 4.84 g

Thus,

\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84

\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84

-694.1618435x+45673.48749\dots =40843.38968\dots

x=\frac{4830.09780\dots }{694.1618435}

x=6.9582

Thus, the mass of Magnesium carbonate = 6.9582 g

\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100

\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%

3 0
3 years ago
Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
2 years ago
Atoms containing the same number of protons and different numbers of neutrons are _____. (1 point)
Vadim26 [7]
I believe that it could be isotopes
3 0
3 years ago
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Predict how many electrons will Li (lithium) most likely be gained or lost
Effectus [21]

Answer:

Lithium will lose about 2 electrons

Making it a cation

4 0
2 years ago
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Which of the following features is common to both acids and bases? A. ability to burn skin B. similar taste C. pH measurements g
Lynna [10]
<h3>Answer:</h3>

            Correct Option-A (Ability to burn skin)

<h3>Explanation:</h3>

                    When skin tissues are exposed to Acids or Bases a chemical burn occurs as both of these substances are corrosive in nature. These burns occur without providing any heat, results from a very fast reaction, are extremely painful and causes damage to structures present under skin.

                    Option-B is incorrect because Acids taste sour, while, Bases taste bitter.

                    Option-C is incorrect because pH of Acids is less than 7 while, pH of Bases is greater than 7.

3 0
3 years ago
Read 2 more answers
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