For this case we have the following system of equations:
Equating both equations we have:
We must find the solutions, for this we factor. We look for two numbers that, when multiplied, result in 4 and when added, result in 5. These numbers are 4 and 1:
Then, the factorized equation is of the form:
Thus, the solutions are:
We look for solutions for the variable "y":
Thus, the system solutions are given by:
ANswer:
Answer:
7
Step-by-step explanation:
mean is average of the numbers
add all values then divide by the numbers
(1+5+8+10+11) / 5
35 / 5 = 7
Answer:
0.667
Step-by-step explanation:
Angle in a circle = 360°
Area of total shaded parts = 60 + 60 = 120°
Area of total unshaded parts = 360-120 = 240°
Probability that a random selected point within the circle falls in the unshaded area
= 240/360
= 2/3
≈ 0.667
I apologize in advance if I made a mistake.
Answer:
The answer to your question is 25 ft
Step-by-step explanation:
Data
height = 20 ft
leg = 15 ft
length of the line = ?
To solve this problem use the Pythagorean theorem.
Height = short leg = b
leg = long leg = a
length of the line = hypotenuse = c
- Substitution
c² = (20)² + (15)²
-Simplification
c² = 400 + 225
c² = 625
-Result
c = 
c = 25 ft
Answer:
a = 1565217.39 ft / s ^ 2
t = 0.001725 seconds
Step-by-step explanation:
The first thing is to use the same system of units therefore we will pass the 28 inches to feet, like this:
28 in * (1 ft / 12 in) = 2.33 ft
Now yes, we can continue, we have the following data:
vi = 0
vf = 2700 ft / s
the equations in this case are as follows:
vf = vi + a * t
vf = a * t
rearranging for a
a = vf / t (1)
now with the position equation we know that:
x = vi * t + (a * t ^ 2) / 2
x = (a * t ^ 2) / 2 (2)
now replacing (1) in (2), we are left with:
x = (vf / t) * (t ^ 2) / 2
knowing that x would be 2.33 ft, which is when the cannonball exits the cannon.
2.33 = 2700 * t / 2
t = 2.33 * 2/2700 = 0.001725 seconds.
and now replace in (1)
a = vf / t = 2700 / 0.001725 = 1565217.39 ft / s ^ 2
