Answer:
The answer is below
Explanation:
i) Since the length of the second clock (radius) is 14 cm = 0.14 m, the distance covered by the second hand in one revelution is:
Distance covered = 2πr = 2π(0.14) = 0.88 m
The time taking to complete one revolution = 60 seconds, hence;
Speed = distance covered in one revolution / time take o complete a revolution
Speed = 0.88 m / 60 s = 0.0147 m/s
ii) Distance covered in 150 s = speed * 150 s = 0.0147 * 150 = 2.2 m
iii) Displacement in 150 seconds = distance from initial position to final position
At 150 s, the hand has covered 2 revolutions and moved 30 s. Hence:
Displacement in 150 seconds = speed * 30 s = 0.0147 * 30 = 0.44 m
1) First of all, let's calculate the potential difference between the initial point (infinite) and the final point (d=0.529x10-10 m) of the electron.
This is given by:

Where E is the electric field generated by the proton, which is
where

is the Coulomb constant and

is the proton charge.
Replacing the electric field formula inside the integral, we obtain

2) Then, we can calculate the work done by the electric field to move the electron (charge

) through this

. The work is given by
About 360 meters I hope this helps
0N. The net force acting on this firework is 0.
The key to solve this problem is using the net force formula based on the diagram shown in the image. Fnet = F1 + F2.....Fn.
Based on the free-body diagram, we have:
The force of gases is Fgases = 9,452N
The force of the rocket Frocket = -9452
Then, the net force acting is:
Fnet = Fgases + Frocket
Fnet = 9,452N - 9,452N = 0N