Answer:
The 40g mass will be attached at 69 cm
Explanation:
First, make a sketch of the meterstick with the masses placed on it;
--------------------------------------------------------------------------
↓ Δ ↓
20 g.................50 cm.................40g
38 cm y cm
Apply principle of moment;
sum of clockwise moment = sum of anticlockwise moment
40y = 20 (38)
40y = 760
y = 760 / 40
y = 19 cm
Therefore, the 40g mass will be attached at 50cm + 19cm = 69 cm
12cm 50 cm 69cm
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↓ Δ ↓
20 g.................50 cm.................40g
38 cm 19 cm
We will have that the graph that describes the scenario is given by graph B.
I’m pretty sure the answer is A
Answer:
B
Volume decreases due to less molecular motion of the gas inside the football.
Explanation:
Assuming that the atmospheric pressure (and therefore, the pressure of the air inside the football) remains constant, this means that we can apply Charle's law, which states that:
"For a fixed amount of gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"
Mathematically:

where
V is the volume of the gas
T is its absolute temperature
In the winter month, the air becomes colder, which means that the temperature of the air (and of the gas inside the football) decreases. As the average kinetic energy of the molecules of a gas is proportional to its absolute temperature, this also means that there will be less molecular motion in the gas, and therefore (as stated by Charle's law) the volume of the gas also decreases.