Answer:
Explanation:
The complete question is here.
A spring is compressed between two objects with unequal masses, m and M, held together. The objects are initially at rest on a horizontal friction less surface. When released, which of the following is true?
a) Kinetic energy is same as before being released
b) The total final kinetic energy is zero.
c) The two objects have equal kinetic energy.
d) The speed of one object is equal to the speed of other.
e) The total final momentum of two objects is zero.
So option e) the total final momentum of two objects is zero.
Rest- to stop doing work or an activity, spend time relaxing
Motion- an act of process of moving
Mitosis- Identical daughter cells
Meiosis- not identical
Answer:
x = 2.69 cm
Explanation:
We are given ;
Density of oil; ρ_oil = 924 kg/m³
Density of wood; ρ_wood = 970 kg/m³
h = 3.79cm
Density of water ( ρ_water) has a constant value of 1000 kg/m³
At equilibrium position, we have;
ρ_wood•g•h - ρ_oil•g•(h - x) - ρ_water•g•x = 0
This is because the density of oil is lower than that of water while density of wood is higher than that of oil but lower than that of water.
x is the distance below the interface between the two liquids is the bottom of the block.
Thus, let's make x the subject;
x = [(ρ_wood - ρ_oil)/(ρ_water - ρ_oil)] x h
Plugging in the relevant values to get ;
x = [(970 - 924)/(1000 - 924)] x 3.79
x = (54/76) x 3.79 = 2.69cm
Answer:
These are all the forces acting on the ball: friction, gravity, and a normal force.
Explanation:
