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3 years ago

Can someone help me solve this for extra credit in school--- please?

Mathematics

1 answer:

STatiana [176]3 years ago

6 0

Answer:

y = - 3x + 2

Step-by-step explanation:

y = - 3x + 5

Slopes of parallel lines are equal

( - 1, 5)

y - 5 = - 3(x + 1)

y = - 3x + 2

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Calculate the number of 1/2 Kg there are in 6 Kg

Semmy [17]

Answer:

12, 1/2 Kg in 6 Kg

Step-by-step explanation:

6 divided by 1/2= 12

3 0

3 years ago

The average weight of a bar of soap should be 6.4 ounces with a standard deviation of 0.2 ounces. A sample of 20 bars of soap fo

-Dominant- [34]

Answer:

The testing statistic is -2.237

Step-by-step explanation:

Test statistic (z) = (sample mean - population mean) ÷ (population standard deviation/√n)

sample mean = 6.3 ounces

population mean = 6.4 ounces

population standard deviation = 0.2 ounces

n (sample size) = 20

z = (6.3 - 6.4) ÷ (0.2/√20) = -0.1 ÷ 0.0447 = -2.237

8 0

4 years ago

The shaded numbers show a pattern in the multiplication table. Which

emmainna [20.7K]

25+1=26 25x4=100 this is the answer

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3 years ago

A bowl is in the shape of a hemisphere (half a sphere) with a diameter of 8 inches. Find the volume of the bowl. Use 3.14 for pi

gayaneshka [121]

Answer: 267.947 (or 267.95) inches^3

Step-by-step explanation:

The formula for the volume of a sphere is $\frac{4}{3}\pi r^{3}$ .

To find your radius (r), divide the diameter of 8 inches by 2. The radius is 4 inches.

Plug in your numbers to the volume equation to get $\frac{4}{3} (3.14)(4^3)$ . The first step is to cube 4 (4*4*4) to get 64. Now your equation is $\frac{4}{3}(3.14)(64)$ .

Multiply 3.14 and 64 to get 200.96. The equation is now $\frac{4}{3}(200.96)$ or $\frac{4}{3} * \frac{200.96}{1}$ .

Multiply the numerators (4 * 200.96) and denominators (1 * 3) to get a final equation of $\frac{803.84}{3}$ .

Finally, divide 803.84 by 3 to get the final answer of 267.947 in^3.

8 0

3 years ago

Change this radical to an algebraic expression with fractional exponents 3√a

aliya0001 [1]

$\bf ~\hspace{7em}\textit{rational exponents}
\\\\
a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n}
~\hspace{10em}
% rational negative exponent
a^{-\frac{ n}{ m}} \implies
\cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\sqrt[3]{a}\implies \sqrt[3]{a^1}\implies a^{\frac{1}{3}}$

5 0

3 years ago