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mars1129 [50]
3 years ago
6

What is the answer I need it urgently ​

Mathematics
1 answer:
nordsb [41]3 years ago
5 0
It’s is 0.............
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If f(x) and its inverse function, f^-1(x), are both plotted on the same coordinate plane, where is their point of intersection?
zloy xaker [14]

Answer:

Step-by-step explanation:

Their point of intersection, assuming there is one, will be somewhere on the line y = x.  This line, y = x, is the line of symmetry between a function and its inverse.  So if the two do in fact intersect, it will be at some point on that line

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3 years ago
Helpppppppppppppppppppppppppppppppppppppp
notka56 [123]
A = L x W
L = W + 3

so equation
A = W (W + 3)
70 = W (W + 3)
or
W (W + 3) = 70

answer
D. last one
W (W + 3) = 70
3 0
3 years ago
HELPPPPPPPP NOWWWW! WILL MARK BRAINLIESTTTTT!
OLEGan [10]
1. slope of the given line = 1/5
    the equation is 
    (y-2)/(x-(-2))=1/5
    x+2=5y-10
    x-5y+12=0

2. slope of the given line = -1/6
    the equation is
    (y-9)/x=6
    y-9=6x
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5 0
3 years ago
Real World Percentages: Roman went shopping for school
Crank
Roman will have to pay $89.67 for his school supplies.
Since you needed help, I’ll show you my work so you know for next time:

85.40 (.05) = 4.27
85.40 + 4.27
= 89.67

I hope this helps :)

8 0
3 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 10 altimeters that are correctly calibrated and two that ar
mart [117]

Answer:  a) 0.545,b) 0.41, c) 0.045, d) not possible.

Step-by-step explanation:

The Sky Ranch is a supplier of aircraft parts. Included in stock are 10 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected without replacement. Let the random variable

x represent the number that are not correctly calibrated.

Complete the probability distribution table.

x={0,1,2,3}

P(x=0)=?

P(x=1)=?

P(x=2)=?

P(x=3)=?

Since we have given that

n = 12

number of good one = 3 from 10

number of bad one = 2

So, P(X=0)=\dfrac{^{10}C_3\times ^2C_0}{^{12}C_3}=\dfrac{120}{220}=0.545

P(X=1) = \dfrac{^{10}C_2\times ^2C_1}{^{12}C_3}=\dfrac{90}{220}=0.41

P(X=2)=\dfrac{^{10}C_1\times ^2C_2}{^{12}C_3}=\dfrac{10}{220}=0.045

P(X=3) is not possible.

Hence, a) 0.545,b) 0.41, c) 0.045, d) not possible.

5 0
3 years ago
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