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NeTakaya
3 years ago
14

There are _______ alkanes with molecular formula C15H32

Chemistry
1 answer:
Mkey [24]3 years ago
8 0

Answer:

There are <u>4</u><u>3</u><u>4</u><u>7</u><u> </u>alkanes with that molecular formula.

I hope this helps

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Which of the following can form a hydrogen bond with the HF molecule?
Lostsunrise [7]

Answer:

helium

(He)

Explanation:

helium

(He)

6 0
3 years ago
The K sp for barium fluoride, BaF2, is 2.45 × 10-5. What is the molar solubility of barium fluoride?
lilavasa [31]

Answer: The molar solubility of barium fluoride is 0.0183 moles/liter.

Explanation:

The equation for the reaction will be as follows:

BaF_2\rightarrow Ba^{2+}+2F^

By Stoichiometry,

1 mole of BaF_2 gives 2 moles of F^- and 1 mole of Ba^{2+}

Thus if solubility of BaF_2 is s moles/liter, solubility of Ba^{2+} is s moles/liter and solubility of F^- is 2s moles/liter

Therefore,  

K_sp=[Ba^{2+}][F^{-}]^2

2.45\times 10^{-5}=[s][2s]^2

4s^3=2.45\times 10^{-5}

s^3=6.12\times 10^{-6}moles/liter

s=0.0183moles/liter

Thus the molar solubility of barium fluoride is 0.0183 moles/liter.

8 0
3 years ago
Compute the equilibrium constant at 25 ∘C for the reaction between Sn2+(aq) and Cd(s), which form Sn(s) and Cd2+(aq). Express yo
Radda [10]

Answer:

6.1×10^8

Explanation:

The reaction is;

Sn^2+(aq) + Cd(s) -----> Sn(s) + Cd^2+(aq)

E°cell = E°cathode - E°anode

E°cathode= -0.14 V

E°anode= -0.40 V

E°cell = -0.14-(-0.40)

E°cell= -0.14+0.40

E°cell= 0.26 V

But

E°cell= 0.0592/n log K

E°cell= 0.0592/2 log K

0.26= 0.0296log K

log K = 0.26/0.0296

log K= 8.7838

K= Antilog (8.7838)

K= 6.1×10^8

8 0
3 years ago
How do you figure out the # of<br> neutrons?
Colt1911 [192]

Answer:

Subtracting the number of protons from the atomic mass.

5 0
3 years ago
Read 2 more answers
Fe2O3 + Al ---&gt; Fe + Al2O3
PIT_PIT [208]

Answer:

Fe2O3 + 2Al \rightarrow 2Fe + Al2O3

Explanation:

Hello!

In this case, when balancing chemical reactions, we must make sure that the atoms of each element are the same at both reactants and products; thus, for the given reaction, we need two iron and aluminum atoms at each side based on their subscripts in the given oxides as shown below:

Fe2O3 + 2Al \rightarrow 2Fe + Al2O3

Best regards!

5 0
3 years ago
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