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NeTakaya
3 years ago
14

There are _______ alkanes with molecular formula C15H32

Chemistry
1 answer:
Mkey [24]3 years ago
8 0

Answer:

There are <u>4</u><u>3</u><u>4</u><u>7</u><u> </u>alkanes with that molecular formula.

I hope this helps

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4 examples of bases​
Vesna [10]

Answer:

Caustic Soda

Limewater

Milk of Magnesia

Bleach

Explanation:

4 0
3 years ago
Container has 28% hydrogen gas and 72%of helium gas at 760 torr pressure. Calculate the partial pressure of helium gas ?
frosja888 [35]

uuuuuuuuuuuuuuuuuuuuuuum i think it the way its shaped

8 0
3 years ago
Which of these electron transitions correspond to absorption of energy and which to emission?
Elan Coil [88]

Answer:

n = 5 to n = 6 absorption

n = 9 to n = 6 emission

n = 6 to n = 4 emission

n = 6 to n = 7 absorption

Explanation:

According to the Bohr's model of the atom. An electron in an atom may absorb energy and move from a lower energy level to a higher energy level. This requires absorption of energy that is equal to the energy difference between the two levels.

Similarly, an electron may move from a higher to a lower energy level, releasing energy that is equal to the energy difference between the higher and the lower level. This is known as emission.

Hence, if the electron is moving from a lower energy level to a higher energy level, an absorption has taken place, e.g n = 5 to n = 6

When an electron moves from a higher energy level to a lower energy level, an emission has taken place e.g n = 9 to n = 6

5 0
3 years ago
According to Hund's Rule, if you were filling the three orbitals at the 2p energy level, you would first put an electron in the
GenaCL600 [577]

Answer:

True.

Explanation:

The Hund's Rule states that all orbitals must be singled occupied before any orbital is doubly occupied, and all the electrons at the singly occupied orbitals have the same spin number. By doing that, the electrons filled the lowest energy orbitals first.

The 2p level has 3 orbitals: 2px, 2py, and 2pz. So, when filling it, first put an electron in the 2px, then in the 2py, then and the 2pz (all with the same spin). After that, the remains electrons can be paired up.

5 0
3 years ago
How many milliliters of a 1:2000 drug "i" solution and a 7% drug "i" solution mixed would make 120ml of a 3.5% solution of drug
yanalaym [24]

To solve this problem, let us say that:

x = volume of 1:2000 drug "i" solution

y = volume of 7% drug "i" solution

Assuming volume additive, then this forms:

x + y = 120 mL

<span>x = 120 – y                    ---> 1</span>

 

1:2000 also refers to 0.0005 concentrations and 7% also refers to 0.07 concentrations. By doing a component balance:

0.0005 x + 0.07 y = 0.035 (120 mL)

0.0005 x + 0.07 y = 4.2

Substituting equation 1 into this derived equation to get an equation in terms of y:

0.0005 (120 – y) + 0.07 y = 4.2

0.06 – 0.0005 y + 0.07 y = 4.2

0.0695 y = 4.14

y = 59.568 mL = 59.57 mL

 

From equation 1, x would be:

x = 120 - 59.57

x = 60.43 mL

 

Answers:

59.57 mL of 1:2000 drug "i" solution

60.43 mL <span>of 7% drug "i" solution</span>

3 0
3 years ago
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