Question

Determine the average volume of 0.20 mol/l NaOH needed to neutralize 25 ml of diluted

Answer 1

12.5 mL of NaOH solution

Explanation:

We have the following chemical reaction in which sodium hydroxide (NaOH) react with acetic acid (CH₃-COOH) to form sodium acetate (CH₃-COONa) and water (H₂O):

NaOH + CH₃-COOH → CH₃-COONa + H₂O

molar concentration = number of moles / volume

number of moles = molar concentration × volume

number of moles of CH₃-COOH = 0.2 × 12.5 = 2.5 mmoles

*typically a vinegar solution have a concentration of acetic acid of 12.5 mol/L.

Taking in account the chemical reaction, we devise the following reasoning:

if        1 mmole of NaOH reacts with 1 mmole of CH₃-COOH

then  X = 2.5 mmoles of NaOH reacts with 2.5 mmoles of CH₃-COOH

volume = number of moles / molar concentration

volume of NaOH solution = 2.5 / 0.2 = 12.5 mL

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