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2 years ago

Salt and water are the general products of which type of reaction?

Chemistry

2 answers:

Sauron [17]2 years ago

5 0

Answer:

Acid Base

Explanation:

Acid base reactions produce water by combining H+ from acids and OH- from bases and the remaining spectator ions form salts

kari74 [83]2 years ago

5 0

Answer:

Acid-based

Explanation:

Acid base reactions produce water by combining H+ from acids and OH- from bases and the remaining spectator ions form salts

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A solution is made by dissolving

nikklg [1K]

Answer:

THE MOLARITY IS 2.22 MOL/DM3

Explanation:

The solution formed was as a result of dissolving 37.5 g of Na2S in 217 g of water

Relative molecular mass of Na2S = ( 23* 2 + 32) = 78 g/mol

Molarity in g/dm3 is the amount of the substance dissolved in 1000 g or 1 L of the solvent. So we have;

37.5 g of Na2S = 217 g of water

( 37.5 * 1000 / 217 ) g = 1000 g of water

So, 172.81 g/dm3 of the solution

So therefore, molarity in mol/dm3 = mol in g/dm3 / molar mass

Molarity = 172.81 g/dm3 / 78 g/mol

Molarity = 2.22 mol/dm3

The molarity of the solution is 2.22 mol/dm3

4 0

3 years ago

How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?

Dominik [7]

The grams of glucose are needed to prepare 400g of a 2.00%(m/m) glucose solution g is calculated as below

=% m/m =mass of the solute/mass of the solution x100

let mass of solute be represented by y
mass of solution = 400 g
% (m/m) = 2% = 2/100

grams of glucose is therefore =2/100 = y/400
by cross multiplication

100y = 800
divide both side by 100

y= 8.0 grams

5 0

3 years ago

Identify the decomposition reaction. 2nh3 + h2so4 ⟶ (nh4)2so4 2nabr + ca(oh)2 ⟶ cabr2 + 2naoh 2 no2 ⟶ 2 o2 + n2 3pb + 2h3po4 ⟶ 3

TEA [102]

A decomposition reaction should look like

A ------> B +C+...

It has to have only one reactant and several products.

2 NO2 ⟶ 2 O2 + N2

7 0

3 years ago

Read 2 more answers

Which of these two statements meets the criteria of a

motikmotik

Hypothesis is a prediction made therefore it is a

4 0

3 years ago

Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange

SIZIF [17.4K]

Answer:

A. 10.0 grams of ethyl butyrate would be synthesized.

B. 57.5% was the percent yield.

C. 7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

Explanation:

$CH_3CH_2CH_2CO_2H(l)+CH_2CH_3OH(l)+H^+\rightarrow CH_3CH_2CH_2CO_2CH_2CH_3(l)+H_2O(l)$

Moles of butanoic acid = $\frac{7.60 g}{88 g/mol}=0.08636 mol$

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

$\frac{1}{1}\times 0.08636 mol=0.08636 mol$ of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 100%

$Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$100\%=\frac{\text{Experimental yield}}{10.0 g}\times 100$

Experimental yield = 10.0 g

10.0 grams of ethyl butyrate would be synthesized.

Theoretical yield of ethyl butyrate = 10.0 g

Experimental yield ethyl butyrate = 5.75 g

Percentage yield of the reaction = ?

$Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$=\frac{5.75 g}{10.0 g}\times 100=57.5\%$

57.5% was the percent yield.

Moles of butanoic acid = $\frac{7.60 g}{88 g/mol}=0.08636 mol$

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

$\frac{1}{1}\times 0.08636 mol=0.08636 mol$ of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 78.0%

$Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$78.0\%=\frac{\text{Experimental yield}}{10.0 g}\times 100$

Experimental yield = 7.80 g

7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

8 0

3 years ago