A car, initially traveling at 5 meters per second north, accelerates to 25 meters per second north in 4.0 seconds. Determine the
1 answer:
Answer:
a = 5 [m/s²].
Explanation:
To solve this equation we must use the following equation of kinematics.
where:
Vf = final velocity = 25 [m/s]
Vo = initial velocity = 5 [m/s]
a = acceleration [m/s²]
t = time = 4 [s]
Note: The positive sign for the acceleration in the above equation means that the car is increasing its velocity.
25 = 5 +a*(4)
25 - 5 = 4*a
20 = 4*a
a = 5 [m/s²]
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Answer:
I. Stopping acceleration = 6 m/s²
II. Stopping distance, S = 75 meters
Explanation:
Given the following data;
Final velocity = 30 m/s
Time = 5 seconds
To find the stopping acceleration;
Mathematically, acceleration is given by the equation;
Substituting into the equation;
Acceleration = 6 m/s²
II. To find the stopping distance, we would use the third equation of motion;
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
30² = 0² + 2*6*S
900 = 12S
S = 900/12
S = 75 meters