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Ivahew [28]
3 years ago
13

Work out the kinetic energy of a 2.5 kg remote-controlled car that is moving at 2 m/s.

Physics
1 answer:
lbvjy [14]3 years ago
8 0

Answer: 5 joules

Explanation:

mass=m=2.5kg

Velocity=v=2m/s

Kinetic energy=ke

ke=(m x v x v)/2

ke=(2.5 x 2 x 2)/2

Ke=10/2

Ke=5

Kinetic energy=5 joules

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What medical technique uses sound wave pulses and their reflections to map structures and organs inside the body?
garri49 [273]

The correct answer is “C” ultrasound. Hope this helps!

7 0
4 years ago
Read 2 more answers
Se aplica una fuerza neta de 25 N a una masa de 10 kg. ¿Cuál es la aceleración dada a la masa?
lys-0071 [83]

Answer:

Se queda

Explanation:

Porque 10 kg es más que 25N

4 0
3 years ago
Problem 6: A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.3
solong [7]

Answer:

v = 5.166 10² m / s

Explanation:

We can solve this exercise using the kinematics equations

           v = v₀ + at

as the bullet starts from rest its initial velocity is zero

           v = a t

let's calculate

           v = 6.3 10⁵   8.2 10⁻⁴

           v = 5.166 10² m / s

3 0
3 years ago
A box is placed on a 30o frictionless incline. What is the acceleration of the box as it slides down the incline
balandron [24]

Answer:

<em>2.78m/s²</em>

Explanation:

Complete question:

<em>A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?</em>

According to Newton's second law of motion:

\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\

Where:

\mu is the coefficient of friction

g is the acceleration due to gravity

Fm is the moving force acting on the body

Ff is the frictional force

m is the mass of the box

a is the acceleration'

Given

\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2

Required

acceleration of the box

Substitute the given parameters into the resulting expression above:

Recall that:

gsin\theta - \mu g cos\theta = a_x\\

9.8sin30 - 0.25(9.8)cos30 = ax

9.8(0.5) - 0.25(9.8)(0.866) = ax

4.9 - 2.1217 = ax

ax = 2.78m/s²

<em>Hence the acceleration of the box as it slides down the incline is 2.78m/s²</em>

5 0
3 years ago
Which statement is correct about the potential energy of a car moving down a ramp?
Paha777 [63]

Potential energy is highest when the car is released at the top of the ramp. The correct answer is option C

Potential energy is the energy possessed by a body when the body is at rest. Potential energy is at time called gravitational potential energy which as a product of mass of the body, acceleration due to gravity and the height attained by the body. That is,

P.E = mgh

When a car is moving down a ramp, the potential energy of the car can never remain the same except the car stop at a certain point.

Whenever a car is moving down a ramp, the potential energy of the car will be highest when the car is release at the top of the ramp. And lowest when the car reaches the bottom of the ramp.

The statement that is correct about the potential energy of a car moving down a ramp is:

Potential energy is highest when the car is released at the top of the ramp.

Therefore, the correct answer is option C

Learn more here: brainly.com/question/17400615

8 0
3 years ago
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