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3 years ago

russell westbrook has a mass of 84.8kg.When jumps to dunk on z 3.04 meter goal,what will be his G.P.E at the apex of his jump?

Physics

1 answer:

horrorfan [7]3 years ago

6 0

The gravitational potential energy is 2526 J

Explanation:

The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in the gravitational field. Near the Earth's surface, it can be calculated as

$GPE=mgh$

where

m is the mass of the body

$g=9.8 m/s^2$ is the acceleration of gravity

h is the height of the object

In this problem, we have

m = 84.8 kg

h = 3.04 m

Substituting,

$GPE=(84.8)(9.8)(3.04)=2526 J$

Learn more about potential energy:

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A 620 nm light falls on a photoelectric surface and electrons with the maximum kinetic energy of 0.14 eV are emitted. (a) Determ

nevsk [136]

Answer:

(a) The work function is 1.86 eV.

(b) The cut off frequency is 450 THz.

Explanation:

incident wavelength = 620 nm

Kinetic energy, K = 0.14 eV

According to the photoelectric equation

E = W + KE

where, W is the work function, KE is the kinetic energy.

(a) Let the work function is W.

$W = E - KE\\W = \frac{h c}{\lambda }- KE\\W =\frac{6.63\times 10^{-34}\times3\times 10^{8}}{620\times 10^{-9}\times 1.6\times 10^{-19}}-0.14\\\\W =1.86 eV$

(b) Let the cut off frequency is f.

W = h f

$1.86\times 1.6\times 10^{-19} = 6.63\times 10^{-34}\times f\\f = 4.5\times 10^{14} Hz =450 THz$

$E = W + eV\\\frac{6.63\times 10^{-34}\times 3\times 10^{8}}{420\times 10^{-9}\times 1.6\times 10^{-19}}=1.8 + eV\\\\V = 1.16 V$

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3 years ago

A rock group is playing in a bar. Sound

Sloan [31]

Answer:

5292.64 m

Explanation:

$dB \rightarrow \textrm{sound level}\\ I \rightarrow \textrm{sound intensity}\\ I_0 \rightarrow \textrm{threshold sound intensity}\\ x \rightarrow \textrm{distance of corresponding to threshold intensity of hearing}$

Taking threshold intensity as $1\times 10^{-12} W/m^{2}$ and since it's a constant then sound intensity for 66.7 dB will be

$66.7\;\rm dB = 10\; log_{10}\;\left(\dfrac{I}{I_0} \right)\\ \dfrac{I}{10^{-12}} = 10^{6.67}\\ I = 4.67735\times 10^{-6}\;\rm W/m^2\\ \boxed{I \approx 4.7\times 10^{-6}\;\rm W/m^2}$

Also, since sound intensity is inversely proportional to the square of the distance of the source then the distance can be given by

$\dfrac{I_1}{I_2} = \dfrac{r^2_2}{r^2_1}\\ \dfrac{4.7\times 10^{-6}\;\rm W/m^2}{10^{-12}\;\rm W/m^2} = \dfrac{x^2\;\rm m}{(5.96\;\rm m)^2}\\ x =\sqrt{28012000}\\ \boxed{x \approx 5292.64;\rm m}$

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3 years ago

What are anticlines and synclines?

vesna_86 [32]

<span>d. They are types of folds created by compressional stresses.</span>.

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3 years ago

Which substance is used to remove rust from metal?

Vlad [161]

Answer : The correct option is, (B) Hydrochloric acid(HCl)

Explanation :

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As we know that the rust is an iron oxide (base) which is removed by an acid.

As per given options, the acid used to remove the rust from the metal is hydrochloric acid and not sulfuric acid because sulfuric acid is an oxidizing agent which oxidizes the metal more.

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Hence, hydrochloric acid is used to remove rust from metal.

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