<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%5E-13%7D%7Ba%5E-6%7D%20" id="TexFormula1" title=" \frac{a^-13}{a^-6} " alt=" \f

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Hoochie [10]

4 years ago

rac{a^-13}{a^-6} " align="absmiddle" class="latex-formula"> Rewrite this expression in the form a^n

Mathematics

1 answer:

dusya [7]4 years ago

8 0

$\dfrac{a^{-13}}{a^{-6}}=a^{-13+6}=a^{-7}$

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4. Rosa plays games at a fair. She can buy 8 game tokens for $ 1. Each game cost 2 tokens. How many games can she play with 120

bezimeni [28]

If each game costs 2 tokens, 120 tokens would equal 60 games.

8 0

3 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

4 years ago

Sin4u=2sin 2u cos 2u

yKpoI14uk [10]

Answer:

If you've learnt sin(A+B) = sinAcosB + cosAsinB,

sin(4u)

= sin(2u+2u)

= sin(2u)cos(2u) + cos(2u)sin(2u)

= 2 sin(2u) cos(2u).

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3 years ago

Solve for x. Thank you.

Bas_tet [7]

Answer:

D) 50/3

Step-by-step explanation:

6/10 = 10/(6+x-6)

6/10 = 10/x

6x = 100

x = 100/6

x = 50/3

4 0

3 years ago

Find two supplementary angles if the measure of one angle is three times the measure of the second

Colt1911 [192]

Hello :
x+3x=180
4x=80
x=180/4
x=45°

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3 years ago