(4 × 5) × 7 = 7 × _________ (4 × 7) 20 (7 - 5) (5 + 7)
1 answer:
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If the 10 books are all different, we have:
• 10 ways of selecting the first book,
,• 9 ways of selecting the second book,
,• 8 ways of selecting the third book,
,• 7 ways of selecting the fourth book.
The total number of ways to arrange 4 of the 10 books is:
Answer
There are 5040 ways of arranging the books.
Answer:
28.6, that is, about 29 are expected to be defective
Step-by-step explanation:
For each battery, there are only two possible outcomes. Either it is defective, or it is not. The probability of a battery being defective is independent of other betteries. So the binomial probability distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
The probability that a battery is defective is 1/14.
This means that
400 batteries.
This means that
How many are expected to be defective?
28.6, that is, about 29 are expected to be defective