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4 years ago

Why do you hear sound when you clap your hands?

2 answers:

7 0

When you move your hands, you have kinetic energy. Once your hands collide, that energy has to go somewhere. It turns into heat and sound waves that creates ripples which disturbs the air particle. This is how sound works, a disturbance in air particles.

iogann1982 [59]4 years ago

6 0

Answer:

Because there are things called sound waves, so you hear a sound when you hit your brother or clap your hands

Explanation:

plain and simple

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Your dog (who weighs 20kg) has just fallen off a cliff! Oh no!! Luckily they were on a leash, and you (who weighs 70kg) was fort

Maksim231197 [3]

Answer:

yes

Explanation:

becasue 70 divided by 0.3 = >20

Hope I helped:)

3 0

3 years ago

If you have 30 amps, how much charge moves past a point in the circuit in 120 seconds.

dolphi86 [110]

Q = I t = 30 x 120 = 3600 C

6 0

4 years ago

A 0.14 kg baseball moving at 23.00 m s is slowed to a stop by a catcher who exerts a constant force of 370 N How long does it ta

Artyom0805 [142]

Answer:

(A) The time taken for the ball to stop is 8.7 x 10⁻³ s

(B) The distance traveled by the baseball before stopping is 0.3 m

Explanation:

Given;

mass of the baseball, m = 0.14 kg

velocity of the baseball, v = 23 m/s

force exerted on the baseball by the catcher, F = 370 N

(A) The time taken for the ball to stop;

$F = ma = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{0.14 \times 23}{370} \\\\t = 8.7\times 10^{-3} \ s\\\\t = 8.7 \ ms$

(B) The distance traveled by the baseball before stopping is calculated as;

acceleration of the ball, $a = \frac{v}{t} = \frac{23}{8.7\times 10^{-3}} = 2643.678 \ m/s^2$

Distance traveled, s;

s = ut + ¹/₂at²

s = (23)(8.7 x 10⁻³) + ¹/₂(2643.678)(8.7 x 10⁻³)²

s = 0.2001 + 0.1001

s = 0.3 m

7 0

3 years ago

You grab a hot cookie sheet out of the oven this is an example of ______ energy transfer.

Maru [420]

I would say Conduction because you are touching the cookie sheet, even though it is hot (so heat) you are physically touching it so it would not be radiation

6 0

3 years ago

Pleaseeeee help me with b, c, and d. There are no angles.

taurus [48]

Answer:

a. 150 J

b. 150 J

c. 0 J

d. 0 J

Explanation:

The given parameters are;

The horizontal force with which the man pulls the canister, F = 50 N

The distance he moves the vacuum cleaner, d = 3.0 m

a. Work done, W = Force applied, F × Distance moved by the force, d

Therefore, for the work done by the 50 N force on the canister, we have;

W = 50 N × 3.0 m = 150 N·m = 150 J

b. Given that he pulls the canister at a constant speed, we have;

The acceleration of the canister, a = 0 m/s²

Therefore, the net force on the canister, $F_{NET}$ = F - $F_{Friction}$ = m × a

Where;

m = The mass of the canister

a = The acceleration of the canister

F = The applied force = 50 N

$F_{Friction}$ = The force of friction

∴ $F_{NET}$ = m × a = m × 0 m/s² = 0 N

Therefore;

$F_{NET}$ = F - $F_{Friction}$ = 0 N

From which we have;

F = $F_{Friction}$ = 50 N (The applied force, F is equal to the force of friction,

The work done by friction = The force of friction × The distance in which the force of friction acts

∴ The work done by friction = $F_{Friction}$ × d - 50 N × 3.0 m = 150 J

The work done by friction = 150 J

c. The normal force, N acts perpendicular to the force of friction

The distance the canister moves in the perpendicular direction, $d_p$ = 0 m

∴ The work done by the normal direction = N × $d_p$ = N × 0 m = 0 J

The work done by the normal direction = 0 J

d. The vacuum weight, W, acts on the same line as the normal force but in the opposite direction to the normal force, N

Therefore, the weight, W, acts perpendicular to the line of motion of canister

The distance the canister moves in the direction of the weight, $d_{wieght}$ = 0 m

Therefore, the work done by the weight = W × $d_{wieght}$ = W × 0 m = 0 J

The work done by the weight = 0 J

7 0

3 years ago