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bija089 [108]
3 years ago
11

What is occurring in the umbra?

Physics
1 answer:
matrenka [14]3 years ago
3 0

Answer:

A. a total solar eclipse

Explanation:

During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth

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Which is the answer
gtnhenbr [62]

Answer:

A: the intensity

Explanation:

the closer the sound, the more intense it is. Think about the ambulance illustration in your text book (assuming you are using a physics textbook) : )

3 0
3 years ago
Read 2 more answers
A jet makes a landing traveling due east with a speed of 120 m/s .
vesna_86 [32]

Average acceleration over a time interval lasting \Delta t is

a_{\rm ave}=\dfrac{\Delta v}{\Delta t}

where \Delta v is the difference in the jet's final and initial velocities. It's coming to a rest, so

a_{\rm ave}=\dfrac{0-120\frac{\rm m}{\rm s}}{13.5\,\rm s}=-8.9\dfrac{\rm m}{\mathrm s^2}

so the average acceleration has magnitude 8.9 m/s^2 and is pointing West (the direction opposite the jet's movement, which should make sense because the jet is slowing down).

7 0
4 years ago
Calculate the angle for the third-order maximum of 580-nm wavelength yellow light falling on double slits separated by 0.100 mm.
alekssr [168]

<u>Answer:</u> The angle of diffraction is 0.498°

<u>Explanation:</u>

To calculate the angle of diffraction, we use the equation given by Bragg, which is:

n\lambda =2d\sin \theta

where,  

n = order of diffraction = 3

\lambda = wavelength of the light = 580nm=5.80\times 10^{-7}m    (Conversion factor:  1m=10^{9}nm )

d = spacing between the crystal planes = 0.100 mm = 1.0\times 10^{-4}       (Conversion factor:  1 m = 1000 mm)

\theta = angle of diffraction = ?

Putting values in above equation:

3\times 5.80\times 10^{-7}=2\times 1.00\times 10^{-4}\sin \theta\\\\\sin \theta = 0.0087\\\\\theta=\sin ^{-1} (0.0087)=0.498

Hence, the angle of diffraction is 0.498°

6 0
3 years ago
Martine also has an eraser.it has a mass of 3g,and a volume if 1cm3.what is its density
shtirl [24]

Answer:

3g/cm³

Explanation:

<em>Use the formula:</em>

density = mass ÷ volume

<em>Substitute (plug in) the values:</em>

density = 3 ÷ 1 = 3g/cm³

4 0
3 years ago
A 6.4-N force pulls horizontally on a 1.5-kg block that slides on a smooth horizontal surface. This block is connected by a hori
Elena L [17]

-- Although it's not explicitly stated in the question,we have to assume that
the surface is frictionless.  I guess that's what "smooth" means.

-- The total mass of both blocks is (1.5 + 0.93) = 2.43 kg. Since they're
connected to each other (by the string), 2.43 kg is the mass you're pulling.

-- Your force is 6.4 N.
                                    Acceleration = (force)/(mass) = 6.4/2.43 m/s²<em>
                                                                 </em>
That's about  <em>2.634 m/s²</em>  <em>

</em>
(I'm going to keep the fraction form handy, because the acceleration has to be
used for the next part of the question, so we'll need it as accurate as possible.)

-- Both blocks accelerate at the same rate. So the force on the rear block (m₂) is

       Force = (mass) x (acceleration) = (0.93) x (6.4/2.43) = <em>2.45 N</em>.

That's the force that's accelerating the little block, so that must be the tension
in the string.


7 0
3 years ago
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