Answer:
my dad is a physics professor so when he comes home i will tell him to answer the question for you
75 percent (calculated percentage %) of what number equals 27? Answer: 36.
Answer:
a. Microwaves—3 and infrared waves—1
Explanation:
Microwaves and infrared waves are both part of the electromagnetic spectrum, but they have different frequency and wavelength.
In particular:
- Microwaves are long-wavelength electromagnetic waves, with wavelength between 1 mm and 1 m. Their wavelength is longer than visible light
- Infrared waves are also long-wavelength electromagnetic waves, but their wavelength is shorter than microwaves: between 700 nm and 1 mm. Their wavelength is also longer than visible light.
The two types of waves are also used for different purposes. In particular:
- Infrared waves are emitted by any hot object, and their intensity depends on the temperature of the object. Therefore, they are used in astronomy to show the heat released by astronomical objects (option 1)
- Microwaves are used to study the Cosmic Microwave Background (CMB). This is electromagnetic radiation that permeates the whole universe, and its wavelength depends inversely on the local temperature. Therefore, areas with longer wavelength have lower temperature, and viceversa. Therefore, microwaves are used to measure temperature differences in space (option 3).
Answer:
In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. ... For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.
Answer:
25.2 m
Explanation:
The horizontal distance traveled s = v × t×cosθ and t = s / (v×cos θ)
The vertical distance traveled h = v × t ×sin θ - 1/2 × g × t^2
Substituting for t, h = s×tan θ- 1/2 × g × s^2 / (v cos θ)^2
Now, Solve for v^2 and get v^2 = g × s^2 ÷ [2 ×cos^2θ × (s×tan θ - h)]
And v^2 = 9.8×3600 / [2×0.535×(60×0.933 - 25] =1065 and v = 32.6 m/s
As a check from the first equation t = 60 / (32.6×0.731) = 2.52 sec
Horizontal distance traveled s = 32.6×cos 43°×2.52 =60 m
Height reached 2×g×h = (v×sin43°)^2
⇒and h = 25.2 m (using 2×g×h =v×y ^2)
Since maximum height is reached at the edge of the cliff the projectile
will not travel beyond the cliff
