Answer:
t = 4 seconds
Explanation:
The question is "The intensity of current flowing through a conductor is 2μA. How long will it take 5x1013 electrons to cross a certain cross section of the conductor?
"
Current, 
No of electrons, 
We need to find how long will it take to given no of electrons to cross a certain cross section of the conductor.
Electric current,

t is time
Also, q = ne

So, it will take 4 seconds.
False its Jupiter than Saturn
Answer:
<u>Given</u><u> </u><u>-</u>
- Initial Velocity, u = 114 m/s
- Final velocity, v = 77 m/s.
- Time taken, t = 9 sec.
<u>To</u><u> </u><u>find</u><u> </u><u>-</u><u> </u>
<u>Solu</u><u>tion</u><u> </u><u>-</u>
Here, using the equation of motion v = u + at we can find the acceleration easily.
★ Here,
- V = Final velocity
- U = Initial Velocity
- A = Acceleration
- T = Time.
<u>Subs</u><u>tituting</u><u> </u><u>the</u><u> </u><u>values</u><u> </u><u>-</u>
→ 77 = 114 + a(9)
→ 9a = 114 - 77
→ 9a = 37
→ a = 37/9
→ a = 4.1 m/s
<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>accele</u><u>ration</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>car</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>4</u><u>.</u><u>1</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>
Answer:
a) There are
electrons in a liter of water.
b) The net charge is -53601707,1 C
Explanation:
a) To find out how many electrons are in a liter of water (equivalent to 1000 grams of water), we have to find out how many molecules of water there are and then multiply it by 10 (e- per molecule).
We can find out how many molecules are by finding the number of moles and then multiplying it by Avogadro's number (number of elements per mol):

b) As all electrons have the same charge, in order to find the net charge of those electrons we have to multiply the charge of a single electron by the number of electrons:

An important clarification is that while the net charge may seem huge, water as a whole is a neutral medium, because there are as many protons as there are electrons, and as they have the same charge, the net charge of water is 0.
You would need to connect a potential difference across a resistor in parallel