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Vesnalui [34]
3 years ago
15

If a net force is greater than 0 Newtons, what is the force?

Physics
1 answer:
goldenfox [79]3 years ago
5 0

Answer:disequilibrium

Explanation:

When the net force is not zero it is called disequilibrium

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explain how the temperature of the earth is maintained and how it’s affected by other factors (6 marks)
nikklg [1K]

Answer:

The temperature of the Earth depends on many factors, including the concentration of greenhouse gases such as water vapour, methane and carbon dioxide. The Earth's temperature also depends on the rates at which light radiation and infrared radiation are: absorbed by the Earth's surface and atmosphere.

6 0
2 years ago
A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
LenaWriter [7]

Answer:

vf = √(vi²+2*(F/m)*D)

Explanation:

Given

Mass of the particle: M

Initial speed of the particle: vi

Force: F

Distance: D

We can apply the formula

F = M*a   ⇒    a = F/m

then we use the equation

vf = √(vi²+2*a*D)

⇒  vf = √(vi²+2*(F/m)*D)

6 0
3 years ago
1. Which of the following types of energy is
Sholpan [36]

Answer:

Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.

5 0
2 years ago
The highest speed attained by a cyclist on level ground is 105 km/h. To attain this speed, the cyclist used a streamlined recumb
omeli [17]

Answer:

The acceleration is 0.133 m/s²

The time taken to build the final speed is 219.32 s

Explanation:

Given;

final speed of the cyclist, v = 105 km/h = 29.17 m/s²

distance traveled by the cyclist, d = 3.2 km = 3,200 m

initial speed, u = 0

Apply the following kinematic equation to determine the acceleration of the cyclist;

v² = u² + 2as

(29.17 )² = 0 + (2 x 3200)a

850.89 = 6400a

a = (850.89 ) / (6400)

a = 0.133 m/s²

The time taken to build up the final speed is given by;

v = u + at

29.17 = 0 + (0.133)t

t = 29.17 / 0.133

t = 219.32 s

4 0
3 years ago
A 4810 kg demolition ball swings at the end of a 12.3 m cable on the arc of a vertical circle. At the lowest point of the swing,
faust18 [17]

The tension in the cable supporting the swing of the ball in the given vertical circle is 47,577.4 N.

<h3>Tension in the cable</h3>

The tension in the cable supporting the swing of the ball is calculated as follows;

T = mg + mac

T = mg + m(v²)/r

T = (4810 x 9.8) + (4810 x 1.06²)/12.3

T = 47,577.4 N

Thus, the tension in the cable supporting the swing of the ball in the given vertical circle is 47,577.4 N.

Learn more about tension here: brainly.com/question/918617

#SPJ1

4 0
1 year ago
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