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KATRIN_1 [288]
3 years ago
11

PLS HELP WILL GIVE BRAINIEST these figures are congruent

Mathematics
1 answer:
geniusboy [140]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Answer is C, only need to move it up and to the right through translation.

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WHICH NUMBER IS LARGER 9.1 OR THE SQUARE ROOT OF 82
kvv77 [185]

Answer: 9.1 is larger

Step-by-step explanation:

9.1 > \sqrt{82}

\sqrt{82} = 9.05

6 0
2 years ago
Read 2 more answers
Joes employer will reimburse him $0.17 per mile driven. If Joe drives 107.78 miles on a business trip,
Alenkinab [10]

Answer:

$18.3236

Step-by-step explanation:

If the employer reimburses $0.17 per mile driven, we just need to multiply $0.17 by the number of miles that Joe drives.

So, the mileage reimbursement for Joe is:

$0.17 * 107.78 = $18.3236

4 0
3 years ago
Please help ! Which net represents the figure?
SCORPION-xisa [38]

Answer:

It is c

Step-by-step explanation:

When you fold it up, it makes a box just like the solid figure.

Have an amazing day!

PLEASE RATE!!

7 0
2 years ago
A baseball player swings and hits a pop fly straight up in the air to the catcher. The height of the baseball in meters t second
tresset_1 [31]
To solve for the time it reach the maximum height, you must solve the first derivative of the function and equate it to zero

<span>h(t) = −4.9t^2 + 14.7t + 1</span>
dh/ dt = -9.8t + 14.7
then equate to zero
-9.8t + 14.7 = 0
solve for t
t = 1.5 s

then the maximum height is when t = 1.5

<span>h(t) = −4.9t^2 + 14.7t + 1
h(1.5) = </span><span>−4.9(1.5)^2 + 14.7(1.5) + 1
h(1.5) = 12.025 m
</span>

4 0
3 years ago
The length of the midsegment of a triangle is always half the length of the side it is parallel to true or false
Vladimir [108]
True. The midsegment of a triangle is halfway up the triangle, and since the top half and the full triangle are similar triangles, its dimensions are proportional.

This means half the height will give half the base (midsegment). So the midsegment is always half the length of the side it's parallel to.
3 0
3 years ago
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