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3 years ago

Someone please help me make a proof for the bottom question

Mathematics

1 answer:

Lerok [7]3 years ago

7 0

Answer:

DB = CA (Proved)

Step-by-step explanation:

Statement 1.

∠D = ∠C, M is the midpoint of DC and ∠1 = ∠2

Reason 1.

Given

Statement 2.

Between Δ DBM and Δ CAM,

(i) DM = CM,

(ii) ∠D = ∠C and

(iii) ∠DMB = ∠CMA

Reason 2.

(i) given

(ii) given and

(iii) ∠ DMB = ∠1 + ∠AMB and ∠CMA = ∠2 + ∠AMB

Since ∠1 = ∠2, so, ∠DMB = ∠CMA.

Statement 3.

Δ DBM ≅ Δ CAM

Reason 3.

By angle-side-angle rule.

Statement 4.

DB = CA

Reason 4.

Corresponding sides of two congruent triangles. (Answer)

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Answer:

The right answer is "5.9". A further solving is provided below.

Step-by-step explanation:

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Initial Magnitude,

M₁ = 3.9

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Now,

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On substituting the values, we get

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On putting the value of "log 120", we get

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iVinArrow [24]

$\fbox{Solution by using Matrix}$

$\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20$

$\text{Rewrite the linear equations above as a matrix}$

$\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right]$

$\text{Apply to Row2 : Row2 + Row1}$

$\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right]$

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$\text{Apply to Row1 : Row1 + 8 Row2}$

$\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right]$

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Answer:

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