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3 years ago

Someone please help me make a proof for the bottom question

Mathematics

1 answer:

Lerok [7]3 years ago

7 0

Answer:

DB = CA (Proved)

Step-by-step explanation:

Statement 1.

∠D = ∠C, M is the midpoint of DC and ∠1 = ∠2

Reason 1.

Given

Statement 2.

Between Δ DBM and Δ CAM,

(i) DM = CM,

(ii) ∠D = ∠C and

(iii) ∠DMB = ∠CMA

Reason 2.

(i) given

(ii) given and

(iii) ∠ DMB = ∠1 + ∠AMB and ∠CMA = ∠2 + ∠AMB

Since ∠1 = ∠2, so, ∠DMB = ∠CMA.

Statement 3.

Δ DBM ≅ Δ CAM

Reason 3.

By angle-side-angle rule.

Statement 4.

DB = CA

Reason 4.

Corresponding sides of two congruent triangles. (Answer)

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Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

What is the length of the major axis of the ellipse (x-7)^2/4+(y+3)^2/16=1

yuradex [85]

$\bf \begin{array}{llll}
\cfrac{(x-{{ h}})^2}{{{ a}}^2}+\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1\\\\ \cfrac{(x-{{ h}})^2}{{{ b}}^2}+\cfrac{(y-{{ k}})^2}{{{ a}}^2}=1
\end{array}\quad 
\begin{cases}
\textit{major axis}=a+a\\
a=\textit{the larger denominator}\\
b=\textit{smaller denominator}
\end{cases}\\\\
-----------------------------\\\\
\cfrac{(x-7)^2}{4}+\cfrac{(y+3)^2}{16}=1\implies \cfrac{(x-7)^2}{2^2}+\cfrac{(y+3)^2}{4^2}=1\quad 
\begin{cases}
a=4\\
b=2
\end{cases}$

6 0

3 years ago

Which equation demonstrates the distributive property? A) 2 (5 + 7) = 2 (7 + 5) B) 2 (5 + 7) = 2 × 5 + 2 × 7 C) (2 × 5) × 7 = 2

Sonbull [250]

Answer:

Step-by-step explanation:

Distributive property is when you distribute the values in a parenthesis with the outside multiplying factor

2*(5+7)= 2*5 + 2*7

2*(12) = 10 +14

24 = 24

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4 0

3 years ago

N+ 12 = -24<br><br> Help please

omeli [17]

Answer:

n = -36

Step-by-step explanation:

The answer is -36 because:

1) We first have to subtract -24 and 12 to find n

-24 - 12 = -36

This is because whenever there are two negative signs, multiply it.

Negative x Negative = Positive

We have to do, 24 + 12 which is 36. Finally, we just put the greater number's sign to the answer. 24 is greater than 12, therefore, we put a negative sign before 36.

Hope this helps!

7 0

3 years ago

2. Kyle owes his sister 24. He gives his sister $15 that he earned mowing

rusak2 [61]

ok so he is owing his sister 24 and he gives her 15

so 24-15=9

but as an addition expression it will be

x+15=24

x=24-15

x=9

3 0

3 years ago