If you cards are only 5,6,7, then the probability of getting even, then even would be zero.
The directions say that the card is not replaced. Therefore, once you pick the 6, there would be no more even cards.
Answer:
Step-by-step explanation:
We can add the two equations to eliminate the variable 
and solve for 
:
Now, we can use substitution to solve for :
(given)
Hope this helps :)
I think the answer I d
but I am not good at math
a) if the two gloves someone receives might both be for the left hand or right hand.
b) if each sister gets one left and one right.
Soln:
a) So i thought about dissectng the problem first into finding the number of ways in which I could make pairs of gloves:
C(12, 2)
then I asked how many ways could the sets of gloves be assigned amongst the 6 sisters:
<span><span>6!</span><span>6!</span></span>
and taking the product of this would give me the amount of ways this could occur:
= C(12,2) * 6!
then for part b)
using this same idea except:
C(6,1) C(6,1) for the left and right glove each .
the C(6,1)*C(6,1)*6!
Right way to think them through?
