Answer:

Step-by-step explanation:
She has a budget of $150, which means that she can spend no more than that amount. Therefore, use the less than or equal to symbol: ≤
Each folder is $2.15, so you are going to multiply: 2.15 × f
Each notebook is $4.60, so you will multiply: 4.6 × n
You want to know how many notebooks and folders you can buy for $150, so add the notebooks and folders.
Make the equation:

:Done
Answer:
The mean is 
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the mean of this normal distribution if the probability of scoring above x = 209 is 0.0228?
This means that when X = 209, Z has a pvalue of 1-0.0228 = 0.9772. So when X = 209, Z = 2.





The mean is 
4x - 26 = 2x - 4....subtract 2x from both sides
4x - 2x - 26 = -4...add 26 to both sides
4x - 2x = -4 + 26...combine terms
2x = 22...divide both sides by 2
x = 22/2 = 11
OR
4x - 26 = 2x - 4.....subtract 4x from both sides
-26 = 2x - 4x - 4....add 4 to both sides
-26 + 4 = 2x - 4x...combine terms
-22 = -2x....divide both sides by -2
-22/-2 = x
11 = x
Answer:

Step-by-step explanation:
Given
Bisector: QS


Required
Determine PQR
Since PQR is bisected to PQS and RQS, we have that

Substitute expressions for PQS and RQS

Collect Like Terms


Divide both sides by 3

Solving for PQR;



Substitute 2 for x



Answer: 12x + 9
Step-by-step explanation:
<u>Given </u>
(6 + 5x) + (7x + 3)
<u>Put like terms together</u>
=5x + 7x + 6 + 3
<u>Combine like terms </u>
=
Hope this helps!! :)
Please let me know if you have any questions