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Alex_Xolod [135]
3 years ago
12

Solve for y 2y= -3x + 4

Mathematics
1 answer:
Margaret [11]3 years ago
5 0

Answer:

y = -1/3x + 2

Step-by-step explanation:

Divide everything by 2

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Question 17/23
disa [49]

Answer:

60%

Step-by-step explanation:

Formula:

Percentage decrease = (amount of decrease)/(original price)

✪ Solve ✪

3.85 - 1.54/3.85 x 100

2.31/3.85 x 100 = 60%

Hence, Percent decrease is 60%

<em>~Lenvy</em>

6 0
2 years ago
(Look at screenshot)
True [87]

#1

Clear shown in graph

  • H(0)=5

#2

No

At. no where graph passes through origin so y intercept is not 0 at anywhere

#3

Domain is x values

  • Domain =[0,oo)

#4

Range is y values set

  • Range=[5,50]
8 0
2 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️Please someone find the kindness in their heart to help me. I have been waiting for 45 minutes and still
Virty [35]
Hey,
I could actually answer the question now, so I am going to put it here as well so the people don't have to read the comments above.

<span>Use the Pythagorean Theorem to find the hypotenuse:<span>a² + b² = c²
5² + 5² = c²
25 + 25 = c²
50 = c²
√50=√(c^2 )
7.07 = c

Answer: 7

Cheers,
Izzy</span></span>
6 0
3 years ago
Activities of tariffs​
Dmitry [639]

Answer:

What??

Step-by-step explanation:

5 0
3 years ago
The cost per week of running a boarding house is partly constant and partly
patriot [66]

Answer:

the cost of running the boarding

house for 600 students is N61,000

Step-by-step explanation:

Let C represents cost

K1 represents first constant

K2 represents second constant

C= k1+k2n

3500 = k1 + 25 k2............. Eqn(1)

6000= k1 + 50 k2 .............. Eqn(2)

Subtract eqn(1) from eqn(2)

2500= 25k2

K2= 2500/25

K2= 100

To get k1 from eqn(1)

3500 = k1 + 25 k2

Substitute the value of k2

3500 = k1 + 25 (100)

3500= k1 +2500

K1= 3500- 2500

K1= 1000

The equation connecting them;

C= 1000+ 100n

The cost of running the boarding

house for 600 students is

n= 600

C= 1000+ 100(600)

C= 1000+60000

C= N 61,0000

6 0
3 years ago
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