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dalvyx [7]
3 years ago
5

Please help!! will give brainliest to best answer simplify sqrt((1-sinx)(1+sinx))

Mathematics
1 answer:
Semmy [17]3 years ago
3 0

Answer:

2) cos theta

Step-by-step explanation:

0 = theta

√(1- sin 0)(1+sin 0)

=√(1 - sin²0)

=√cos²0

= cos 0 => (cos theta)

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One True Love? A survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each pe
sertanlavr [38]

Answer:

99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                                 P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of people who disagree with the statement = \frac{1812}{2625} = 0.69

           n = sample of respondents = 2625

           p = population proportion of people who disagree with statement

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

<u>So, 99% confidence interval for the population proportion, p is ;</u>

P(-2.58 < N(0,1) < 2.58) = 0.99  {As the critical value of z at 0.5% level

                                                   of significance are -2.58 & 2.58}  

P(-2.58 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.58) = 0.99

P( -2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<u>99% confidence interval for p</u> = [ \hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

= [ 0.69-2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } } , 0.69+2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } } ]

 = [0.667 , 0.713]

Therefore, 99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

5 0
4 years ago
Crawling Crayfish!
boyakko [2]

Answer: Crayfish, 25 s

Step-by-step explanation:

Given

The length of race is 60 cm

Flicker gets a 10 cm head-start

Cray fish covers 6 cm in 5 s i.e. its speed is

\Rightarrow \dfrac{6}{5}=1.2\ cm/s

Flicker covers 4 cm in 5 s, its speed is

\Rightarrow \dfrac{4}{5}=0.8\ cm/s

Time taken by Cray fish to cover the race is

\Rightarrow t_1=\dfrac{60}{1.2}\\\\\Rightarrow t_1=50\ s

Time taken by flicker to cover race with 10 cm head start

\Rightarrow t_2=\dfrac{60-10}{0.8}\\\\\Rightarrow t_2=62.5\ s

Time taken by crayfish is less. Hence, crayfish wins the race

When they both covers the same distance, they tied momentarily i.e.

\Rightarrow 1.2t=10+0.8t\\\Rightarrow 0.4t=10\\\\\Rightarrow t=\dfrac{10}{0.4}\\\\\Rightarrow t=25\ s

After 25 s, they tied the race.

5 0
3 years ago
Need help Last weekend, Raul's basketball team played in a
Darina [25.2K]

Answer:

40%

Step-by-step explanation:

First off, 1/5 is equal to 20%. If you're diving something into 5ths, you can do 100 / 5, which is 20. So you know that Raul scored at least 20% of the points. His friend Jake ALSO scores 20% of the teams points, making 20 + 20 = 40%. Therefore, 40% of the teams points were scored by Raul and Jake.

6 0
3 years ago
PLEASE HELPPPP
Illusion [34]

Answer:

  • p = 3/10

Step-by-step explanation:

<u>Given equation:</u>

  • 20p = 6

<u>Divide both sides by 20:</u>

  • p = 6/20

<u>Simplify:</u>

  • p = 3/10
6 0
3 years ago
Read 2 more answers
Find the nth term of the arithmetic sequences<br> a1=5,d=6,n=11
ki77a [65]

here's the solution,

  • n = 11
  • a = 5 ( a = first term )
  • d = 6 ( d = common difference )

we know,

=》

nth  \: \: term \:  = a   \: + (n - 1) \times d

=》

11th \:  \: term   = 5 + (11 - 1) \times 6

=》

11th \:  \: term = 5 + (10 \times 6)

=》

11th \:  \: term  = 5 + 60

=》

11th \:  \: term = 65

nth term ( 11th term ) = 65

3 0
3 years ago
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