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svlad2 [7]
3 years ago
13

Helpp plssssss :) .....

Chemistry
1 answer:
MaRussiya [10]3 years ago
4 0
B is right yuh yuh yuh yuh
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Neutralization Reactions
PolarNik [594]

Answer:

its a option neutralization takes place between acid and base plz mark me branliest

3 0
3 years ago
During radioactive decay, the __________ isotope decays into a ____________ isotope that has a different ___________________ num
SVETLANKA909090 [29]

Answer: Please find answer in explanation column

Explanation:

During radioactive decay, the __unstable ________ isotope decays into a _stable ___________ isotope that has a different ____proton _______________ number

Or

During radioactive decay, the _ unstable parent nuclide ________ isotope decays into a _stable daughter nuclide ___________ isotope that has a different ____proton _______________ number.

There are 3 types of radioactive decay;alpha, beta and gamma, Of which the above clearly explains the beta decay. In beta decay, the unstable isotope having excess neutrons  will undergo a beta decay emitting a beta particle.( ⁰₋₁e) causing the nucleus to loose a neutron but gain a proton.

Some heavy unstable isotopes which undergo radioactive (beta decay ) to become stable isotopes  are phosphorus-32, strontium-90, iodine-131

Using Strontium 90 as an example , we have

⁹⁰₃₈St ----->⁹⁰₃₉Y + ⁰₋₁e

Strontium an unstable isotope undergoes a beta radioactive decay to form Yttrium.

 

3 0
3 years ago
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is the max
jolli1 [7]

<u>Answer:</u> The mass of aluminium chloride that can be formed are 46.3 g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  ....(1)  

  • <u>For Aluminium:</u>

Given mass of aluminium = 32 g  

Molar mass of aluminium = 26.98 g/mol

Putting values in above equation, we get:  

\text{Moles of aluminium}=\frac{32g}{26.98g/mol}=1.186mol

  • <u>For Chlorine:</u>

Given mass of chlorine = 37 g  

Molar mass of chlorine = 71 g/mol

Putting values in above equation, we get:  

\text{Moles of chlorine gas}=\frac{37g}{71g/mol}=0.521mol

For the given chemical equation:

2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)

By Stoichiometry of the reaction:

3 moles of chlorine gas is reacting with 2 moles of aluminium.

So, 0.521 moles of chlorine gas will react with = \frac{2}{3}\times 0.521=0.347moles of aluminium.

As, given amount of aluminium is more than the required amount. Thus, it is considered as an excess reagent.

So, chlorine gas is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

3 moles of chlorine gas is producing 2 moles of aluminium chloride

So,  0.521 moles of chlorine gas will react with = \frac{2}{3}\times 0.521=0.347moles of aluminium chloride.

Now, calculating the mass of aluminium chloride by using equation 1, we get:

Moles of aluminium chloride = 0.347 moles

Molar mass of aluminium chloride = 133.34 g/mol

Putting all the values in equation 1, we get:

0.347mol=\frac{\text{Mass of aluminium chloride}}{133.34g/mol}\\\\\text{Mass of aluminium chloride}=46.3g

Hence, the mass of aluminium chloride that can be formed are 46.3 g

7 0
4 years ago
When vinegar and baking soda are combined bubbles begin to form. Bubbles are evidence of a chemical reaction because they
Varvara68 [4.7K]

Answer:

bubbled

Explanation:

its simple they bubbled

signs of chemical reactions are change of

odor

bubbles

solid turns liquid

liquid turns solid

change of color

7 0
4 years ago
If you start with 512 grams of aluminum and 1147 grams of copper chloride to make aluminum chloride and copper, what is the limi
Archy [21]

First you need to calculate the number of moles of aluminium and copper chloride.

number of moles = mass / molecular weight

moles of Al = 512 / 27 = 19 moles

moles of CuCl = 1147 / 99 = 11.6 moles

From the reaction you see that:

if        2 moles of Al will react with 3 moles of CuCl

then  19 moles of Al will react with X moles of CuCl

X = (19 × 3) / 2 = 28.5 moles of CuCl, way more that 11.6 moles of CuCl wich is the quantity you have. So the copper chloride is the limiting reagent.

6 0
3 years ago
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