Question

If the reaction is begun with an initial PH3 concentration of 0.95 M, what will be the concentration of PH3 after 30.50 s

Answer 1

Answer:

$[PH_3]=0.30M$ but see detailed explanation, please.

Explanation:

Hello there!

In this case, unfortunately, we are not given the rate constant but we can set up a reaction according to the information available on the internet:

$4PH_3\rightarrow P_4+6H_2$

Whose rate constant is 0.0375/s. In such a way, it is possible infer that this is first-order reaction whose integrated rate law is:

$[PH_3]=[PH_3]_0exp(-kt)$

Thus, given the initial concentration, rate constant and elapsed time, the final concentration of PH3 would be:

$[PH_3]=(0.95M)exp(-30.50s*0.0375/s)$

$[PH_3]=0.30M$

However, it is important to keep in mind this result may vary according to your actual question.

Regards!