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tekilochka [14]
3 years ago
14

If the reaction is begun with an initial PH3 concentration of 0.95 M, what will be the concentration of PH3 after 30.50 s

Chemistry
1 answer:
Dovator [93]3 years ago
3 0

Answer:

[PH_3]=0.30M but see detailed explanation, please.

Explanation:

Hello there!

In this case, unfortunately, we are not given the rate constant but we can set up a reaction according to the information available on the internet:

4PH_3\rightarrow P_4+6H_2

Whose rate constant is 0.0375/s. In such a way, it is possible infer that this is first-order reaction whose integrated rate law is:

[PH_3]=[PH_3]_0exp(-kt)

Thus, given the initial concentration, rate constant and elapsed time, the final concentration of PH3 would be:

[PH_3]=(0.95M)exp(-30.50s*0.0375/s)\\\\

[PH_3]=0.30M

However, it is important to keep in mind this result may vary according to your actual question.

Regards!

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<u>Answer:</u>

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By stoichiometry of the reaction:

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  • <u>For b:</u>

By stoichiometry of the reaction:

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So, 0.724 moles of salicylic acid will produce = \frac{1}{1}\times 0.724=0.724mol of aspirin.

Now, to calculate the mass of aspirin, we use equation 1:

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Putting values in equation 1, we get:

0.724mol=\frac{\text{Mass of aspirin}}{180.158g/mol}\\\\\text{Mass of aspirin}=130.43g

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