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morpeh [17]
3 years ago
6

Which ordered pairs in the form (x, y) are solutions to the equation (x + 6)y = 9? Choose all answers that are correct.  A.(−5,

9)  B.(−3, 3)  C.(3, 1)  D.(7, 9)
Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0
<span>So we need to find the solutions to the equation (x+6)y=9 so we can arrange them in pair (x,y). We simply plug in the numbers into the equation. First pair (-5,9), we get (-5+6)9=9 so 1=1 and that is true, so first pair works. Second pair: (-3+6)3=9 we get (3)3=9 and 9=9 so second pair also works. Third pair: (3+6)1=9 we get 9=9, also works. Fourth pair: (7+6)9=9 we get 13*9=9 and 117=9 which is false so the fourth pair can't be a solution for the equation. The correct answers are A, B and C.</span>
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Mrs. drennan keeps a bag of small prizes to distribute to her students. She likes to keep at least three times as many prizes in
Ber [7]
26x3=78
78-x=72
x=6
She needs to buy at least 6 more to have enough for 26 students

8 0
3 years ago
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The fox population in a certain region has a continuous growth rate of 6 percent per year. It is estimated that the population i
Ksivusya [100]

Answer:

P(t) = 9800(1.06)^t

P(8) = 15620

Step-by-step explanation:

For growth the equation is

y = ab^x  where a is the initial value, b = 1 plus the growth percentage, and x is the number of years

P(t) = 9800 (1+.06) ^t

P(t) = 9800(1.06)^t

from 2000 to 2008 is 8 years

P(8) = 9800(1.06)^8

15619.71113040224768

We can only have whole foxes

P(8) = 15620

3 0
2 years ago
NEED ASAP CORRECT ANSWER GETS BRAINLIESt
andriy [413]

Answer:

QS = 8x - 2

Step-by-step explanation:

QS = QR + RS

QS = 6x - 11 + 2x + 9

QS = 8x - 2

8 0
2 years ago
HELP ASAP PLZZZZ
Tcecarenko [31]
QUESTION 1

The given system of equations is

3d - e = 7...eqn(1)
d + e = 5...eqn(2)

To solve by linear combination, we add equation (1) to equation (2) to get,

3d  + d= 7 + 5


4d = 12


We divide through by 4 to obtain,


d =  \frac{12}{4}


d = 3


We put d=3 into equation (2) to get,



3+ e = 5


e = 5 - 3


e = 2


\boxed {The \: solution \: is  \: (3, 2)}



QUESTION 2


The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)


To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

4x - 3x = 5 - 3



This implies that,

x = 2


Put x=3 into equation (1) to get,

4(2) + y = 5

8+ y = 5


y = 5 - 8



y =  - 3

The solution is

(2,-3)



QUESTION 3

We want to solve the system;


a – 2b = –2 ....eqn(1)


2a + 2b = 14...eqn(2)

by linear combination.


We need to add equation (1) to equation (2) to eliminate b.


This implies that,

2a + a = 14 +  - 2




Simplify,

3a = 12



Divide both sides by 3 to get,


a = 4
Put a=4 into equation (2) to obtain,



2(4) + 2b = 14


8 + 2b = 14
2b = 14 - 8


2b = 6


b = 3


The ordered pair in the form (a, b) is

(4,3)



QUESTION 4

The given system of equations is


11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)


We subtract equation (2) from equation (1) to get,


11x - 3x = 18 - 2


8x = 16


x = 2


Put x=2 into equation (2) to obtain,


3(2) + 4y = 2


This implies that,


6 + 4y = 2


4y = 2 - 6


4y =  - 4


y=-1

The correct answer is (2,-1).




QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2


We add the two equations to eliminate e.


This implies that,

2d + d = 8 + 4


3d = 12



We divide both sides by 3 to get,


d = 4


We put d=4 into equation (2) to get,

4 - e = 4

- e = 4 - 4



- e = 0



e = 0


The solution is

(4,0)
7 0
3 years ago
lan ran 24 laps in a charity run and then walked 0.2 kilometer to the presentation table the total; distance lan traveled was 29
QveST [7]

Answer:

Step-by-step explanation:

1.225km is equal to each laps

Step-by-step explanation:

Since Kristy total distance traveled = 29.6km

And Kristy ran 24 laps and later walk 0.2km. it simply implies that

Total distance traveled = distance covered running + distance covered walking

Since we know that

Total distance traveled = 29.6km

distance covered running = 24 laps

distance covered walking = 0.2km

Distance covered running in km = total distance traveled - distance covered walking

Distance covered running in km = 29.6km - 0.2km = 29.4km.

To now find the distance for each lap.

Since we have:

Distance covered running in km = 29.4km.

Distance covered running in lap = 24 laps

i.e

24 laps = 29.4km

1 lap = x

Use cross-multiple

24 laps * x = 29.4km × 1 lap

x = 29.4km / 24

x = 1.225km

Therefore

1.225km is equal to each laps.

8 0
2 years ago
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