Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
Answer:
Addition of Polynomials
1Add: 3x3 – 5x2 + 8x + 10, 15x3 – 6x – 23, 9x2 – 4x + 15 and -8x3 + 2x2 – 7x.
2Add: 7a + 5b, 6a – 6b + 3c and -5a + 7b + 4c. ...
3Add: 3a2 + ab – b2, -a2 + 2ab + 3b2 and 3a2 – 10ab + 4b2 ...
4Add: 5x + 3y, 4x – 4y + z and -3x + 5y + 2z. First we need to write in the addition form. ...
Step-by-step explanation:
Hope it helps ya ItzAlex
Is there a none option? if not then it has to be B.
Answer:
The answer is D.
Step-by-step explanation:
She forgot to find the square root of 7225.
B. The y-intercept is 0 so it can't be C or D and the slope is 5/1. How I remember this is rise/run. Hope this helps!
