I believe the answer is the fourth option.
9p^2-6p5q^2 in standard form it would be: 9p^2+5q^2-6p
Answer:
Step-by-step explanation:
we know that
<u><em>Combinations</em></u> are a way to calculate the total outcomes of an event where order of the outcomes does not matter.
To calculate combinations, we will use the formula
where
n represents the total number of items
r represents the number of items being chosen at a time.
In this problem
substitute
simplify
Answer: 0.38
Step-by-step explanation:
Since the variable x is represented by a standard normal distribution, the probability of x > 0.3 will be calculated thus:
P(x > 0.3)
Then, we will use a standard normal table
P(z > 0.3)
= 1 - p(z < 0.3)
= 1 - 0.62
= 0.38
Therefore, p(x > 0.3) = 0.38
The probability of x > 0.3 is 0.38.
The weight average of the coordinates is -4
<h3>How to determine the
weight average?</h3>
The complete question is given as:
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. And we need to calculate the weight average
The given parameters are:
- Coordinate -6 has a weight of 3
- Coordinate 2 has a weight of 1.
The weight average is then calculated as:
Weight average = Sum of (Weigh * Coordinate)/Sum of Weights
So, we have:
Weight average = (-6 * 3 + 2 * 1)/(3 +1)
Evaluate the products
Weight average = (-18 + 2)/(3 +1)
Evaluate the sum
Weight average = -16/4
Evaluate the quotient
Weight average = -4
Hence, the weight average of the coordinates is -4
Read more about average at
brainly.com/question/20118982
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<u>Complete question</u>
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. Calculate the weight average
