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Elis [28]
3 years ago
5

Four times as much as the sum of 1/5 and 2/3

Mathematics
1 answer:
Oxana [17]3 years ago
7 0

Answer:

4*[1/5+2/3]

4[3/15+10/15]

4[13/15]

4*13/15

=52/15

=3  7/15

Step-by-step explanation:

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Write a quadratic function to model the vertical motion for each​ situation, given ​h(t) equals negative 16t squared plus v0t+h0
Mashcka [7]

Answer:

hmax = 194 ft

The maximum height is 194 ft

Step-by-step explanation:

According to the given equation for the model of the vertical motion. The height at any point in time can be written as;

h(t) = -16t^2 + v0t + h0 .......1

Where;

h(t) = height at time t

t = time

v0 = initial velocity = 96 ft/s

h0 = initial height = 50 ft

To determine the maximum height we need to differentiate the equation 1 to find the time at which it reaches maximum height;

At the highest point/height h' = dh/dt = 0

h'(t) = -32t +v0 = 0

-32t + v0 = 0

t = v0/32

t = 96/32

t = 3 s

At t=3 it is at maximum height.

The maximum height can be derived from equation 1;

Substituting the values of t,v0,h0 into equation 1;

h(t) = -16t^2 + v0t + h0 .......1

hmax = -16(3)^2 + 96(3) + 50 = 194 ft

hmax = 194 ft

The maximum height is 194 ft

5 0
3 years ago
A volleyball reaches its maximum height of 13 feet, 3 seconds after its served. Which of the following quadratics could model th
yan [13]
I'm pretty sure that It is d
6 0
3 years ago
©<br>Find the area of a circle with radius, r = 6.53m.<br>Give your answer rounded to 2 DP.​
natita [175]

Answer:

133.96 meters squared

Step-by-step explanation:

To calculate the area of a circle, simply multiply the radius squared, by pi.

A = pi x r^2

A = pi x 6.53^2

A = pi x 42.6409

A = 133.9603382

The area of the circle is approximately 133.96 meters squared.

Hope this helps! :)

7 0
3 years ago
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If the number is divisible by both 2 and 3 then we can say the number is divided by
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That number is divisible by 6.
7 0
3 years ago
If f(x) = 7x^2 - 3x +1 and g(x) = 3x - 2, find the following by matching.
Cloud [144]

f(x) = 7x² - 3x + 1

g(x) = 3x - 2


1. g(0) This means that x is 0, so you can plug in 0 for x in the equation:

g(x) = 3x - 2

g(0) = 3(0) - 2

g(0) = -2


2. g(1)    x is 1

g(x) = 3x - 2

g(1) = 3(1) - 2

g(1) = 3 - 2

g(1) = 1


3. f(1)     x is 1

f(x) = 7x²- 3x + 1

f(1) = 7(1)² - 3(1) + 1

f(1) = 7 - 3 + 1

f(1) = 5


4. f(x) = 7x²- 3x + 1

f(-2) = 7(-2)²- 3(-2) + 1

f(-2) = 7(4) + 6 + 1

f(-2) = 28 + 7

f(-2) = 35

4 0
3 years ago
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