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Virty [35]
3 years ago
9

Solve for x. 13x + 7 = 5x - 20

Mathematics
2 answers:
myrzilka [38]3 years ago
7 0
The answer is -27/8= -3.375
den301095 [7]3 years ago
5 0
<span>Answer is x= −<span>​27/8 <span>​​</span>
</span></span>Simplify <span>13x+7-5x<span>13x+7−5x</span></span><span> to </span><span>8x+7<span>8x+<span>7
</span></span></span><span><span>8x+7=−20</span>Then Subtract </span>7<span> from both sides
Which would then be </span>8x=−20−7

<span><span>
</span></span>
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4. Use the process outlined in the lesson to approximate the number 2√3. Use the approximation √3 ≈ 1.732 050 8.
jeka57 [31]

Answer:

sequence of five intervals

(1) 2  < 2^{\sqrt{3} }   < 2^{2}

(2) 2^{1.7}  < 2^{\sqrt{3} }    < 2^{1.8}

(3) 2^{1.73}  < 2^{\sqrt{3} }    < 2^{1.74}

(4) 2^{1.732}  < 2^{\sqrt{3} }    < 2^{1.733}

(5) 2^{1.7320}  < 2^{\sqrt{3} }    < 2^{1.7321}

Step-by-step explanation:

as per question given data      

√3 ≈ 1.732 050 8 

to find out      

sequence of five intervals

solution      

as we have given that √3 value that is here

√3 ≈ 1.732 050 8            ........................1

so  

when we find 2^{\sqrt{3} }           ................2

put here √3 value in equation number  2  

we get  2^{\sqrt{3} }   that is  3.322    

so    

sequence of five intervals

(1) 2  < 2^{\sqrt{3} }   < 2^{2}

(2) 2^{1.7}  < 2^{\sqrt{3} }    < 2^{1.8}

(3) 2^{1.73}  < 2^{\sqrt{3} }    < 2^{1.74}

(4) 2^{1.732}  < 2^{\sqrt{3} }    < 2^{1.733}

(5) 2^{1.7320}  < 2^{\sqrt{3} }    < 2^{1.7321}

8 0
2 years ago
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