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Nookie1986 [14]
3 years ago
7

Helpppppppppppppppp it is due now

Mathematics
2 answers:
Fudgin [204]3 years ago
5 0

Hey mate hope its help you...

Paha777 [63]3 years ago
5 0
The answer is : 120


you add 15+45 then subtract by 180
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Jon reads 25 pages in 30 minutes. If Jon reads 200 pages at this same rate, how long will it take him?
kupik [55]
It will take Jon 240 minutes or 4 hours.
5 0
3 years ago
What is the answer?
taurus [48]

x^2y^3(1-x^3y)

This is because you can at most, factor out x² and y³

5 0
3 years ago
How to find the points of a line that is perpendicular to a line you only know the slope of
Lady bird [3.3K]

Answer:

Write the new equation in slope-intercept form.  Replace the old slope with the new slope.  Replace the y-intercept's value with a variable (b).

5 0
3 years ago
Read 2 more answers
Which equation represents the circle described? (in picture)
Sedaia [141]
You are right. In circle equation we have =r² so the correct answer will be C od D.  But we have to calculate the center of a circle.

x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24

Complete the square:

x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2

And we have:

(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\
(x-4)^2+(y-3)^2-16-9=-24\\\\(x-4)^2+(y-3)^2-25=-24\quad|+25\\\\\boxed{(x-4)^2+(y-3)^2=1}

So the answer is C (the same left side of equation).
6 0
3 years ago
Use the coordinate plane to plot the points (6, 0) and (0, 5). Which statement is true? (0, 5) is located on the x-axis. (0, 5)
m_a_m_a [10]

Answer:

(6, 0) is located on the x-axis

Explanation:

For a point to be on the x-axis, its y-value must equal 0. (6, 0) has an x-value of 6 and a y-value of 0.

"(0, 5) is located at the origin" is not true because the origin is at (0, 0).

"(0, 5) is located on the x-axis" is not true because its y-value is 5, not 0.

"(6, 0) is located at the origin" is not true because the origin is at (0, 0).

6 0
2 years ago
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