6x / x²
the reciprocal of a number n is 
the reciprocal of
is 
The product of a number and it's reciprocal = 1
Ok, so:
For Part A, we have: P(Z|A)=P(Z and A)/P(A)
And if we replace, we got:
P(Z|A) = (0.15)/(0.25) and this is equal to 0.6.
For Part B, we have: P(A|Z)=P(Z and A)/P(Z)
P(A|Z) = (0.15)/(0.73) and this is equal to 0.205.
The polynomial

may have solutions which are the divisors of -20, therefore -20 has the following divisors:

.
If x=1, then

,
if x=-1, then

,
if x=2, then

, then x=2 is a solution and you have the first factor (x-2).
If x=-2, then

, then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of

, then the polynomial

is a divisor of

and dividing the polynomial

by

you obtain

.
I am looking for the same answer if anyone knows it
Answer:
hope this helps you.................