Answer:

Step-by-step explanation:

Multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.



Or, You can simply reduce the fraction with 2, which results to 1.
Hope I helped!
Best regards! :D
The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
Answer:
4y^3/2
Step-by-step explanation:
The 4 will remain 4 so we'll leave that alone. √y³ can be written as y^3/2. The way I like to remember how to write fractional exponents is that the index of the radical is the denominator of the fractional exponent and the exponent inside the radical is the numerator.
X = 11 x cos(22) = 10.199 = 10.2