Answer:
6, 10, 8
Step-by-step explanation:
aₙ= aₙ₋₁ - (aₙ₋₂ - 4)= aₙ₋₁ - aₙ₋₂ + 4
a₅= -2
a₆= 0
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aₙ₋₂= aₙ₋₁ - aₙ + 4
- a₄= a₅- a₆ + 4 = -2 - 0 + 4 = 2
- a₃= a₄ - a₅ + 4 = 2 - (-2) + 4 = 8
- a₂= a₃ - a₄ + 4 = 8 - 2 + 4 = 10
- a₁= a₂ - a₃ + 4 = 10 - 8 + 4 = 6
The first 3 terms: 6, 10 and 8
Answer: −
2 x -12
Step-by-step explanation:
its already simplifed foo
Answer:
This function is an even-degree polynomial, so the ends go off in the same directions, just like every quadratic I've ever graphed. Since the leading coefficient of this even-degree polynomial is positive, the ends came in and left out the top of the picture, just like every positive quadratic you've ever graphed. All even-degree polynomials behave, on their ends, like quadratics.
Step-by-step explanation:
Let us bear in mind the equivalent value of these coins:
One dime = $0.10
One quarter = $0.25
Let x = number of dimes
y<span> = number of quarters</span>
Since the boy has 70 coins in total, we can say that:
<span>x + y = </span><span>70 </span>(can be written as x = 70 – y)
Since the boy has a total of $12.40, we can say that:
0.10x + 0.25y = 12.40
To solve this problem, we need to solve this system of equation. We have to substitute the value of x as written in the first equation (x = 70 –y)
0.10(70 – y) + 0.25y = 12.40
7 – 0.10y + 0.25y = 12.40
0.15y = 5.40
y = 36
X = 70 – 36
X = 34
Therefore,<span> the boys </span>has<span> 34 dimes and 36 quarters. To check our answer, we just have to check if his money would total $12.40.</span>
34 dimes = $3.40
36 dimes = $9.00
<span>Total </span><span>$12.40</span>
Answer:
141, meaning that there will be two real solutions
Step-by-step explanation:
The discriminant of a quadratic is 
, which in this case is:
Since the discriminant is positive and not zero, there will be two real solutions to this equation. This is because when the discriminant is negative, and you take the square root of it, you get a negative number. If you take the square root of 0, you get 0, which means that there will only be one solution to the equation.
Hope this helps!
