Ask question

Ask question

All categories

jarptica [38.1K]

3 years ago

10

What is an equilibrant?

1 answer:

Stolb23 [73]3 years ago

4 0

I’m pretty sure it is an object with a net force of zero. All forces are balanced and EQUAL

You might be interested in

PLEASE HELP!!!! Thank you!

V125BC [204]

it would be a chain reaction and a wave

6 0

3 years ago

I had gotten this one wrong please help thank you

Nata [24]

Check the 1st 2nd 3rd and 4th boxes

4 0

4 years ago

If you hold your hand over a pot of boiling water, it feels hot. Explain how the boiling water is transforming heat to your hand

MakcuM [25]

I don't no if this helps but the body heat from your hand causes the liquid to boil, which in turn makes the liquid evaporate, turning it to gas. The expanding gas pushes the liquid upwards and when you release your hand, equilibrium is re-established.

8 0

3 years ago

Read 2 more answers

A modern compact fluorescent lamp contains 1.4 mg of mercury (Hg). If each mercury atom in the lamp were to emit a single photon

Reika [66]

Answer:

A. 1.64 J

Explanation:

First of all, we need to find how many moles correspond to 1.4 mg of mercury. We have:

$n=\frac{m}{M_m}$

where

n is the number of moles

m = 1.4 mg = 0.0014 g is the mass of mercury

Mm = 200.6 g/mol is the molar mass of mercury

Substituting, we find

$n=\frac{0.0014 g}{200.6 g/mol}=7.0\cdot 10^{-6} mol$

Now we have to find the number of atoms contained in this sample of mercury, which is given by:

$N=n N_A$

where

n is the number of moles

$N_A=6.022\cdot 10^{23} mol^{-1}$ is the Avogadro number

Substituting,

$N=(7.0\cdot 10^{-6} mol)(6.022\cdot 10^{23} mol^{-1})=4.22\cdot 10^{18}$ atoms

The energy emitted by each atom (the energy of one photon) is

$E_1 = \frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

$\lambda=508 nm=5.08\cdot 10^{-7}nm$ is the wavelength

Substituting,

$E_1 = \frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{5.08\cdot 10^{-7} m}=3.92\cdot 10^{-19} J$

And so, the total energy emitted by the sample is

$E=nE_1 = (4.22\cdot 10^{18} )(3.92\cdot 10^{-19}J)=1.64 J$

4 0

3 years ago

A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 second

Natali5045456 [20]

The feather's vertical position $y$ is determined by

$y=\dfrac12g_{\text{moon}}t^2$

We take the feather's starting position to be the origin, and the downward direction to be positive. Then

$y=\dfrac12\left(1.63\,\dfrac{\mathrm m}{\mathrm s^2}\right)\left(9.00\,\mathrm s\right)^2=66.0\,\mathrm m$

so the answer is D.

3 0

3 years ago