The hawk’s centripetal acceleration is 2.23 m/s²
The magnitude of the acceleration under new conditions is 2.316 m/s²
radius of the horizontal arc = 10.3 m
the initial constant speed = 4.8 m/s
we know that the centripetal acceleration is given by
= 
= 23.04/10.3
= 2.23 m/s²
It continues to fly but now with some tangential acceleration
= 0.63 m/s²
therefore the net value of acceleration is given by the resultant of the centripetal acceleration and the tangential acceleration
so
= 
= 
= 2.316 m/s²
So the magnitude of net acceleration will become 2.316 m/s².
learn more about acceleration here :
brainly.com/question/11560829
#SPJ4
Answer:
the answer is helium you already know that because im in college on my way to the military next week bless me
Explanation:
Answer and explanation:
A.
Muon travelled straight down towards the earth. Therefore the tree moves up in the rest frame of muon (option a)
B.
In muon rest frame it travels Zero meters
C.
Distance, d = Velocity, v * Time, s


D.
Distance from the top of the mountain to the tree is the same as the distance travelled by the tree in the muons rest frame
that is same as in part C which is 594m
E.
Using lorentz contraction
In the rest frame of someone standing on the mountain
the distance is given by




d' = 258.92m
F.
in the rest frame of someone standing on the mountain,
muon moves straight down
Answer:
Collision force will be same in both the cases.
Explanation:
A perfectly inelastic collision is said to take place when a system loses the amount of its Kinetic Energy at its maximum. In a perfectly inelastic collision, the colliding particles stick to each other. In such a collision, kinetic energy is lost by combining the two bodies with each other.
In situation 1:
Speed of Car A, 
Speed of Car B, 
Relative speed of car A and car B, 
Now, in the situation 2:
Speed of car A, 
Speed of car B, 
Relative speed of car A and car B, 
Therefore, Car A and Car B both have the same relative speed, v = 10 m/s
<h3><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u></h3>
- Energy Transferre=11KJ
- Efficiency=35%
<h3>☆Usefully transferred energy:-</h3>





