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Lady_Fox [76]
3 years ago
11

Given the following frequencies, calculate the corresponding periods. a. 60 Hz b. 8 MHz c. 140 kHz d. 2.4 GHz

Physics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

The frequency can be defined as the inverse of the period, that is, it can be expressed as

T = \frac{1}{f}

Here,

T = Period

f = Frequency

For each value we only need to replace the value and do the calculation:

PART A)

T = \frac{1}{f}

T = \frac{1}{60Hz}

T = 0.0166s

PART B)

T = \frac{1}{f}

T = \frac{1}{8*10^6}

T = 1.25*10^{-7} s

PART C)

T = \frac{1}{f}

T = \frac{1}{140*10^{3}}

T = 7.14*10^{-6}s

PART D)

T = \frac{1}{f}

T = \frac{1}{2.4*10^{9}}

T = 4.166*10^{-10}s

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Likurg_2 [28]

Power is the RATE of use, flow, or transfer of energy.

1 watt = 1 joule PER SECOND.

The correct choice is ' <em>a</em> '.

3 0
3 years ago
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Dump Tower is 96 stories tall. A small, 1.2-kg object is dropped over the side of the roof of the tower and accelerates toward t
laiz [17]

Answer:

6.0 s

98 m/s

Explanation:

The radius of the planet is much bigger than the height of the tower, so we will assume the acceleration is constant.  Neglect air resistance.

Acceleration due to gravity on this planet is:

a = GM / r²

a = (6.67×10⁻¹¹ m³/kg/s²) (2.7 × 1.48×10²³ kg) / (1.7 × 750,000 m)²

a = 16.4 m/s²

The height of the tower is:

Δy = 96 × 3.05 m

Δy = 293 m

Given v₀ = 0 m/s, find t and v.

Δy = v₀ t + ½ at²

(293 m) = (0 m/s) t + ½ (16.4 m/s²) t²

t = 6.0 s

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (16.4 m/s²) (293 m)

v = 98 m/s

8 0
3 years ago
compared to an object that does not roll, but instead slides without friction, should a rolling object be released from the same
Zinaida [17]

Answer:

from a lesser hight

Explanation:

because you need less force

hope its right if it is mark brainlyest ;)

6 0
2 years ago
Which of the following statements is an accurate description of vibrations?
dexar [7]
<span>So we want to know what statement is an accurate description of vibrations. So humans can hear sound frequencies from 20-20000 Hz. Below 20 Hz is infra sound and above 20000 Hz is ultra sound. Humans cant hear both infra sound and ultra sound so the correct answer is A.</span>
6 0
3 years ago
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Rahul has 2 bulbs connected across two cells in a simple circuits shown. How can he make the bulbs glow dimmer?
Ray Of Light [21]

Answer:

in the parallel connection the light bulbs shine less than in the series connection

Explanation:

In a series circuit the current through the whole circuit is the same, therefore the power (brightness) of each bulb is

           P = i² R

where R is the resistance of each bulb and i the current of the circuit.

If we connect the light bulbs and the cells in parallel, the current in the circuit is the sum of the east that passes through each light bulb,

            i = i₁ + i₂

if the two light bulbs are the same

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           i₁ = i / 2

so the power of each bulb is is

           P = i₁² R

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Therefore we see that in the parallel connection the light bulbs shine less than in the series connection

3 0
3 years ago
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