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Lady_Fox [76]
3 years ago
11

Given the following frequencies, calculate the corresponding periods. a. 60 Hz b. 8 MHz c. 140 kHz d. 2.4 GHz

Physics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

The frequency can be defined as the inverse of the period, that is, it can be expressed as

T = \frac{1}{f}

Here,

T = Period

f = Frequency

For each value we only need to replace the value and do the calculation:

PART A)

T = \frac{1}{f}

T = \frac{1}{60Hz}

T = 0.0166s

PART B)

T = \frac{1}{f}

T = \frac{1}{8*10^6}

T = 1.25*10^{-7} s

PART C)

T = \frac{1}{f}

T = \frac{1}{140*10^{3}}

T = 7.14*10^{-6}s

PART D)

T = \frac{1}{f}

T = \frac{1}{2.4*10^{9}}

T = 4.166*10^{-10}s

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            Em₀ = U = mg y

Final. Low point just before the crash

           Emf = K = ½ m v²

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           v = √ 2 g y

Let's calculate

           v = √ (2 9.8 0.05)

           v = 0.99 m / s

1) the moment before the crash is

           p₀ = m v

           p₀ = 0.221 0.99

           p₀ = 0.219 kg m / s

After the collision, the car's speed is zero, so its moment is zero.

           p = 0

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           Δp = p - p₀

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