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Colt1911 [192]
3 years ago
15

A mass of 2 kg traveling at 3 m/s undergoes a one-dimensional elastic collision with a group of four 1kg masses that are at rest

in contact with each other and lined up in the same direction as
the velocity of the 2-kg mass. As a result of the collision
Physics
1 answer:
alukav5142 [94]3 years ago
6 0
2kg + 3 kg = 5 kg as result of the conclusion
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Which of the following is true about this lever?
zysi [14]

As we can see here the lever has two forces at two ends

1. 300 N

2. 200 N

now we need to find the Torque on the lever about the fulcrum

so we will have

1. clockwise torque due to force at right end is

\tau_1 = d_1F_1

\tau_1 = 6(200) = 1200 Nm

2. counterclockwise torque due to force at left end

\tau_2 = d_2F_2

\tau_2 = 1(300) = 300 Nm

so as per above calculations we can see that net torque on the lever is clockwise as it has more torque in clockwise direction

so <u>it will rotate clockwise</u>

6 0
3 years ago
Read 2 more answers
If the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave?
GaryK [48]

Answer:

f = 614.28 Hz

Explanation:

Given that, the length of the air column in the test tube is 14.0 cm. It can be assumed that the speed of sound in air is 344 m/s. The test tube is a kind of tube which has a closed end. The frequency in of standing wave in a closed end tube is given by :

f=\dfrac{nv}{4l}

f=\dfrac{1\times 344}{4\times 0.14}

f = 614.28 Hz

So, the frequency of the this standing wave is 614.28 Hz. Hence, this is the required solution.

4 0
4 years ago
If A vector = i^-j^+k^ then unit vector in the direction of A vector
Novosadov [1.4K]

If <em>A</em> = <em>i</em> - <em>j</em> + <em>k</em>, then the magnitude of <em>A</em> is

||<em>A</em>|| = √(1² + (-1)² + 1²) = √3

Then the unit vector in the direction of <em>A</em> is 1/||A|| multiplied by <em>A</em> :

<em>u</em> = <em>A</em>/||<em>A</em>|| = (<em>i</em> - <em>j</em> + <em>k</em>)/√3

(choice D)

6 0
3 years ago
A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling
Natalka [10]

Answer:

H = 5 m

Explanation:

As the person leaves the slide horizontally so the time taken by the person to hit the water is given as

t = 0.672 s

so we can find the vertical velocity by which person will hit the water using kinematics

v_y = u_y + at

v_y = 0 + (9.81)(0.672)

v_y = 6.6 m/s

now the speed of the person at the end of the slide is given as

v = \frac{L}{t}

v = \frac{5}{0.672}

v_x = 7.44 m/s

now by energy conservation we can find the initial height

mgH = \frac{1}{2}m(v_x^2 + v_y^2)

H = \frac{1}{2g}(v_x^2 + v_y^2)

H = \frac{1}{2(9.81)}(7.44^2 + 6.6^2)

H = 5 m

6 0
3 years ago
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The total amount of power that a star radiates is called its
Ede4ka [16]
Luminosity is the total amount of power a star radiate I think :)
3 0
3 years ago
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