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Helen [10]
3 years ago
8

SCIENCE HELP!!!!!!!!!!!!!!!!!!111

Physics
2 answers:
bulgar [2K]3 years ago
6 0

The answer is 12 joules

kykrilka [37]3 years ago
5 0

Joules/Meter = Newton

So, the answer equals C) 12 Joules

12 divided by 4 meters = 3 Newtons

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What is the mass of an object which has a force of 600 N acting on it and is travelling
Paha777 [63]

Answer:

<em>The mass of the object is 40 Kg</em>

Explanation:

<u>Net Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object is:

F = m.a

Where:

a = acceleration of the object.

m = mass of the object.

The mass can be calculated by solving for m:

\displaystyle m=\frac{F}{a}

The object has a net force of F=600 N acting on it and travels at a=15\ m/s^2, thus the mas is:

\displaystyle m=\frac{600}{15}

m = 40 Kg

The mass of the object is 40 Kg

6 0
3 years ago
Physic help????????????????
maxonik [38]

My personal understanding and opinion is that ALL of those questions
should be part of an assessment of Physical Activity Readiness.


4 0
3 years ago
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the difference between any two successive numbers always seems to be _ more than the preceding difference
erma4kov [3.2K]

Here's li^{}nk to the answer:

cutt^{}.ly/4Rq^{}tIvk

6 0
2 years ago
Read 2 more answers
Se golpea una pelota de golf de manera que su velocidad inicial forma un ángulo de 45° con la horizontal. La pelota alcanza el s
nordsb [41]

Answer:

42m/s

6.06s

Explanation:

To find the initial velocity and time in which the ball is fling over the ground you use the following formulas:

x_{max}=\frac{v_o^2sin(2\theta)}{g}\\\\x_{max}=vt_{max}

θ: angle = 45°

vo: initial velocity

g: gravitational constant = 9.8m/s^2

x_max: max distance = 180 m

t_max: max time

by replacing the values of the parameters and do vo the subject of the first formula you obtain:

v_o=\sqrt{\frac{gx_{max}}{sin(2\theta)}}\\\\v_o=\sqrt{\frac{(9.8m/s^2)(180m)}{sin(2(45\°))}}=42\frac{m}{s}

with this value of vo you calculate the max time:

t_{max}=\frac{x_{max}}{v}=\frac{x_{max}}{v_ocos(45\°)}\\\\t_{max}=\frac{180m}{(42m/s)cos(45\°)}=6.06s

hence, the initial velocity of the ball is 42m/s and the time in which the ball is in the air is 6.06s

- - - - - - - - - - - - -- - - - - - - - - - - - - -

TRANSLATION:

Para encontrar la velocidad inicial y el tiempo en el que la pelota está volando sobre el suelo, use las siguientes fórmulas:

θ: ángulo = 45 °

vo: velocidad inicial

g: constante gravitacional = 9.8m / s ^ 2

x_max: distancia máxima = 180 m

t_max: tiempo máximo

reemplazando los valores de los parámetros y haciendo el tema de la primera fórmula que obtiene:

con este valor de vo usted calcula el tiempo máximo:

por lo tanto, la velocidad inicial de la pelota es de 42 m / sy el tiempo en que la pelota está en el aire es de 6.06 s

4 0
2 years ago
A student is creating a table with properties of electromagnetic and mechanical waves.
katen-ka-za [31]

Answer:

The property of the wave marked X is related to the source of the wave

Explanation:

The source of of origin of waves

Electromagnetic wave are waves that consists of varying electric and magnetic field that vibrate perpendicular to each other and to the direction of propagation of the wave and they are therefore transverse waves and transfer energy

Electromagnetic waves originate from the vibration of charged particles that gives off varying electric and magnetic fields

Mechanical waves are defined as waves that require a material medium such as air, water, metal, plastic, stretched leather, or wood to propagate

Mechanical waves originate from vibration of the particles of a medium

Sound waves which is a form of longitudinal mechanical waves that propagates by the vibration of the particles of a given medium about a point parallel to the direction of propagation of the wave.

8 0
3 years ago
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