a.) K 2=K 1 +GmM( r 21− r 11)=2.2×10 7J
b.) K 2 +GmM( r 11− r 21)=6.9×10 7 J
Applying Law of Energy conservation :
K 1+U 1
=K 2+U 2
⇒K 1− r 1GmM
=K 2− r 2 GmM
where M=5.0×10 23kg,r1
=> R=3.0×10 6m and m=10kg
(a) If K 1
=5.0×10 7J and r 2
=4.0×10 6 m, then the above equation leads to
K 2=K 1 +GmM (r 21− r 11)=2.2×10 7J
(b) In this case, we require K 2
=0 and r2
=8.0×10 6m, and solve for K 1:K 1
=K 2 +GmM (r 11− r 21)=6.9×10 7 J
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Explanation:
The solute does not have to be in the same physical state as the solvent, but the physical state of the solvent usually determines the state of the solution. As long as the solute and solvent combine to give a homogeneous solution, the solute is said to be soluble in the solvent.
Answer: equal to 3 m/s
Explanation:
Speed of golf ball will be equal to 3 m/s because in Perfect Elastic Collision Energy is conserved .
So speed of golf ball will be same in order to Satisfy
Initial Kinetic Energy =Final Kinetic Energy
Considering Bowling ball remains at rest after collision other wise some energy will also be acquired by bowling ball which automatically decreases the amount of Kinetic Energy of golf ball resulting its speed to decrease by some extent.
Answer:
the answer is d
Explanation:
you get exhausted at the middle because it is steep.
Answer:571.09 kJ
Explanation:
Given
Temperature of cooling water from engine exit
After Passing through the radiator its temperature decreases to 
specific heat of water
Volume of water 
density of water 
Thus mass of water
Heat transferred to the surrounding is equal to heat absorbed by cooling water
