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tresset_1 [31]
3 years ago
14

X3 − 2y2 − 3x3 + z4 if x = 3, y = 5, and z = −3

Mathematics
2 answers:
Andre45 [30]3 years ago
4 0
X³ - 2y² - 3x³ +z^4
(substitute the values)

3³ - 2(5)² - 3(3)³ + (-3)^4
27 - 10² - 9³ + 81
27 - 100 - 729 + 81
-73 - 648
-721

So, the answer is -721

HOPE THIS HELPS!!!!
Olenka [21]3 years ago
4 0
9 - 10 - 27 + -12 = -40
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The linear model d = 0.15+.35t represents the data found for the dive of a local swim team where t represents the duration of th
jek_recluse [69]

Answer:

B   That if the dive was increased by 1 second, the depth would increase by about .35 feet.

Step-by-step explanation:

The coefficient of the variable represents the rate of change

4 0
2 years ago
How to do this because I don't know my class work
salantis [7]
I assume the answer is 1/4
5 0
3 years ago
The work of a student to solve the equation 2(5y − 2) = 12 + 6y is shown below:
jolli1 [7]
We know that Step 1 is correct, because it is just a restatement of the equation. Therefore, we can eliminate Step 1:

2(5y – 2) = 12 + 6y

In Step 2, the student tried using the Distributive Property. The Distributive Property can be written as one of the two following formulas:

a(b + c) = ab + ac
a(b – c) = ab – ac

In this case, we'll use the second formula. Substitute any known values into the equation above and simplify:

2(5y – 2) = 2(5y) – 2(2)
2(5y – 2) = 10y – 4

In Step 2, the student calculated 2(5y – 2) to equal 7y – 4. However, we have just proven that 2(5y – 2) is equal to 10y – 4.

The student first made an error in Step 2, and the correct step is:

Step 2: 10y – 4 = 12 + 6y

I hope this helps!
8 0
3 years ago
Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha
Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

a = 20 --- tree distance from north gate

b =14 --- movement from south gate

c = 1775 --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

\triangle ADE \sim \triangle ACB --- similar triangles

So, we have the following equivalent ratios

AE:DE = AB:CB

Where:

AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775

Substitute these in the above equation

20:x/2 = 20 + x + 14: 1775

20:x/2 = x + 34: 1775

Express as fraction

\frac{20}{x/2} = \frac{x + 34}{1775}

\frac{40}{x} = \frac{x + 34}{1775}

Cross multiply

x *(x + 34) = 1775 * 40

Open bracket

x^2 + 34x = 71000

Rewrite as:

x^2 + 34x - 71000 = 0

Expand

x^2 + 284x -250x - 71000 = 0

Factorize

x(x + 284) -250(x + 284)= 0

Factor out x + 284

(x - 250)(x + 284)= 0

Split

x - 250 = 0 \ or\ x + 284= 0

Solve for x

x = 250 \ or\ x =- 284

x can't be negative;

So:

x = 250

6 0
3 years ago
Jenny and Hanan are collecting clothes for a clothing drive. Hanan collected 1/2 as many bags of clothes as Jenny did. If Jenny
kozerog [31]

Answer:

3/8

Step-by-step explanation:

3/4 is the same as 6/8.

6/8 divided by 2 is 3/8.

6 0
3 years ago
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