Answer:
The ratio of the intensities is roughly 6:1.
Step-by-step explanation:
The intensity I() of an earthquake wave is given by:
<em>where P: is the power ans d: is the distance. </em>
Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:
<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km </em>
Therefore, the ratio of the intensities is roughly 6:1.
I hope it helps you!
1/2 of angle D is given as 32 degrees.
The 3 inside angles need to add up to 180 degrees.
Angle B is a right angle, which is 90.
Angle C = 180 - 90 - 32 = 58 degrees.
Elsa's answer is incorrect since there is a solution of the given equation. In the given logarithmic problem, we need to simplify the problem by transposing log2(3x+5) in the opposite side. The equation will now be log2x-log2(3x+5)=4. Using properties of logarithm, we further simplify the problem into a new form log (2x/6x+10)=4. Then transform the equation into base form 10^4=(2x/6x+10) and proceed in solving for x value which is equal to 1.667.
Answer:
9.12 + 9.12 = 18.24 inches
Step-by-step explanation:
Diameter = 23 inches (given)
Radius = 11.5 inches
2 Chords of length = 14 inches ( You didn't specify if the 14 inches is for both chords or for a single cord. I'll assume it's for two cords 14 and 14inches apart.
To clearly solve this, we'll make some mild assumptions.
Let the perpendicular distance of the chords from the center of the circle to represented as " x and y"
Therefore:
x^2 + 7^2 = 11.5 ^ 2
x^2 + 49 = 132.25
x^2 = 132.25 - 49
x^2 = 83.25
x = √ 83.25
x = 9.12 inches
Since the cords have thesame length (Assumed from the way the question was structured, the distance would still be thesame)
y^2 + 7^2 = 11.5 ^ 2
y^2 + 49 = 132.25
y^2 = 132.25 - 49
y^2 = 83.25
y = √ 83.25
y = 9.12 inches
Therefore, the distance will be :
9.12 + 9.12 = 18.24 inches
Have fun!
