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Nookie1986 [14]
3 years ago
12

​(8x−9​)+​(10x+10​) simply the answer

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

18x + 1

Step-by-step explanation: combine like terms so 8x +10x + (-9)+10

neonofarm [45]3 years ago
3 0

Answer:The answer is 28

Step-by-step explanation:

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Find h(g(n)) when h(n) = 2n + 5<br> and g(n) = n +4
Evgen [1.6K]

Answer:

2n+13

Step-by-step explanation:

h(g(n))\\h(n)=2n+5\\g(n)=n+4\\h(n+4)=2(n+4)+5\\=2n+8+5\\=2n+13

5 0
3 years ago
The smoothie shop offers five fruits strawberry, banana, pineapple, mango, and blueberry. If Tracy wants to order a smoothie wit
Paha777 [63]
15 I helped someone with this question already so I know its right

6 0
3 years ago
Read 2 more answers
In circle P with mNRQ = 60°, find the angle measure of minor arc NQ
Galina-37 [17]

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)

Multiply by 2 on both sides.

$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)

$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)

Substitute m∠NRQ = 60°.

$\Rightarrow 2\times 60^\circ=m(ar NQ)

$\Rightarrow 120^\circ=m(ar NQ)

The measure of minor arc NQ is 120°.

8 0
3 years ago
The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}

\dfrac{5}{12} \times 1250

Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}

\dfrac{5}{18} \times 1250^2

∴

Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]

Finally, the standard deviation  of the insurance payment is:

= \sqrt{Var(I(x))}

= 1250 \sqrt{\dfrac{5}{48}}

≅ 404

4 0
3 years ago
7. The height of a ball in meters is modeled
s344n2d4d5 [400]

Answer:

the ball is in the air for 8 seconds

Step-by-step explanation:

f(x) = y

when y = 0, the ball would've travelled through the air over the final time of flight.

0 = -5x^2 + 40x + 0

use quadratic equation to find the value of x

x = (-b ± √b^2 - 4 • a • c) / 2 • a

x = (-40 ± √40^2 - 4 • -5 • 0) / 2 • -5

x = (-40 ± √1600) / - 10

x = (-40 ± 40) / - 10

x = 0 or x = 8

7 0
2 years ago
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