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Brums [2.3K]
3 years ago
5

How does the theory of relativity explain the gravity exerted by massive objects?

Physics
1 answer:
Maslowich3 years ago
8 0

(D)

Explanation:

The more massive an object is, the greater is the curvature that they produce on the space-time around it.

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you will hear a higher pitch due to a higher frequency.

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3 years ago
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A. All of the stars move in a clockwise path around Polaris.
densk [106]

Explanation:

Polaris also called North star is the brightest star in the the constellation Ursa Minor. It remains stationary whereas entire north sky move around it. It the point of north celestial pole.

A) False. This is because  All of the stars move in a counterclockwise path around Polaris.

B) False. Reason stated above.

C) True, As the stars move towards the Polaris there orbital radius decreases as they move smaller circles.

D) False, As the stars move towards the Polaris there orbital radius decreases as they move smaller circles.

E) True.

F) False.

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3 years ago
A volleyball is served at a speed of 8 / at an angle 35° above the horizontal. What is the speed of the ball when received by th
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3 years ago
if the moon were somehow knocked out of orbit and flew off into outer space, what are the possible effects on the earth?
Anarel [89]
<h2>Answers:</h2>

<u>The possible effects on the earth will be</u><u> 1) No light during night 2) No tides</u>

<h2>Explanation:</h2>

As we know that tides are caused by the differential gravitational force on the equatorial regions by the moon. So if the Moon escapes from Earth, the main effect would be the lack of tides on Earth The region closer to the Moon experiences more gravitational force than the region on Earth away from the Moon. Other effects will be no more Moon to light up the night sky and no more solar eclipses.

5 0
3 years ago
The quantity of charge through a conductor is modeled as Q = (3.00 mC/s4)t4 − (2.00 mC/s)t + 9.00 mC. What is the current (in A)
Mumz [18]

Answer:

The current at time t = 4.00 s is 0.766 A.

Explanation:

Given that,

The quantity of charge through a conductor is modeled as :

Q=(3t^4-2t+9)\ mC

We need to find the current (in A) at time t = 4.00 s. We know that the rate of change of electric charge is called electric current. It is given by :

I=\dfrac{dQ}{dt}\\\\I=\dfrac{d(3t^4-2t+9)}{dt}\\\\I=12t^3-2

At t = 4 s

I=12(4)^3-2=766\ mC/s\\\\I=0.766\ C/s=0.766\ A

So, the current at time t = 4.00 s is 0.766 A. Hence, this is the required solution.

7 0
3 years ago
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