1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brums [2.3K]
3 years ago
5

How does the theory of relativity explain the gravity exerted by massive objects?

Physics
1 answer:
Maslowich3 years ago
8 0

(D)

Explanation:

The more massive an object is, the greater is the curvature that they produce on the space-time around it.

You might be interested in
Imagine you are sitting on a sled and someone is about to push you down a hill. Which statement is accurate?
Dima020 [189]

The answer is:

Forces acting on the sled are paired with equal and opposite forces.

The explanation:

About to push you, this means that he doesn't push yet. If the sled is on level ground and no one is pushing it, then forces are equal and opposite.

The gravity force pulls down and the ground pushes up.

This is Newton's third law:

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

We can also see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool.

6 0
3 years ago
Read 2 more answers
As in the video, we apply a charge +Q to the half-shell that carries the electroscope. This time, we also apply a charge –Q to t
Andreyy89

Answer:

Explanation:

When the positively charged half shell is brought in contact with the electroscope, its needle deflects due to charge present on the shell.

When the negatively charged half shell is brought in contact with the positively charged shell , the positive and negative charge present on each shell neutralises each other  .So both the shells lose their charges .The positive half shell also loses all its charges

When we separate the half shells , there will be no deflection  in the electroscope because both the shell have already lost their charges and they have become neutral bodies . So they will not be able to produce any deflection in the electroscope.

4 0
4 years ago
Read 2 more answers
which phenomenon is most directly responsible for earth’s magnetic field? Earth spinning on its axis. The moon's gravitational p
Scorpion4ik [409]
Earth spinning on its axis
5 0
4 years ago
Write down the effect of humidity and temperature on the speed of sound.​
finlep [7]

Answer:

The speed of sound is affected by temperature and humidity. Because it is less dense, sound passes through hot air faster than it passes through cold air. ... The attenuation of sound in air is affected by the relative humidity. Dry air absorbs far more acoustical energy than does moist air.

4 0
3 years ago
A luggage handler pulls a 20.0 kg suitcase up a ramp inclined at 25 degrees above the horizontal by a force F of magnitude 145 N
Nonamiya [84]

Answer:

A) 667 J

B) 381.4 J

C) 0 J

D) 245.4 J

E) 40.2J

F) 2 m/s

Explanation:

Let g = 9.81 m/s2

A) The work done on the suitcase is the product of the force applied and the distance travelled:

w = Fs = 145 * 4.6 = 667 J

B) The work done by gravitational force the dot product between the gravity vector and the distance vector

W_g = \vec{P}\vec{s} = mgs sin\alpha = 20*9.81*4.6*sin25^o = 381.4 J

C) As the normal force vector is perpendicular to the distance vector, the work done by the normal force is 0

D) The work done on the suitcase by friction force is the product of the force applied and the distance travelled, whereas friction force is the product of normal force and coefficient

W_f = F_fs = \mu N s = \mu s mgcos\alpha = 0.3* 4.6 * 20*9.81*cos25^o = 245.4 J

E) The total workdone on the suite case would be the pulling work subtracted by gravity work and friction work

W = w – W_g – W_f = 667 – 381.4 – 245.4 = 40.2 J

F) As the suit case has 0 kinetic and potential energy at the bottom, and the total work done is converted to kinetic energy at 4.6 m along the ramp, we can conclude that:

E_k = W = 40.2 j

mv^2/2 = 40.2

20v^2/2 = 40.2

10v^2 = 40.2

v^2 = 4.02

v = \sqrt{4.02} = 2 m/s  

3 0
3 years ago
Other questions:
  • A ___ is a point on a standing wave that appears to be stationary
    13·2 answers
  • A heavy log will float on water
    5·2 answers
  • URNOW Lidl llIIS 15 TIUta WiCluie U water!<br> ify-What two kinds of matter are pure substances?
    14·1 answer
  • Write the y-equation for a wave traveling in the positive x-direction with frequency 200 Hz, speed 400 m/s, and amplitude 0.010
    15·1 answer
  • 1. Will biogas burn with a flame. why?
    14·2 answers
  • Three charges lie along the x axis. The positive charge q1 = 15 μC is at x= 2.0 m and the positive charge q2 = 6.0μC is at the o
    13·2 answers
  • Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez
    12·1 answer
  • what different forms of energy are demonstrated by tv remote, flashlight, string lol ights, clock, and Toys​
    7·1 answer
  • Hi, I was wondering what is the use of a temperature sensor since the sensor wouldn't be fully immersed in the hydrogen.
    6·1 answer
  • You want to lean your dad's ladder on a smooth wall. If the mass of ladder is 4.42 kg and coefficient
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!