6x2=12m
6x18=108
12m+108
Simplified: m+9 bc 12/12 and 108/12
Answer:
Approximate linear dimension is 2 light years.
Explanation:
Radius of the spiral galaxy r = 62000 LY
Thickness of the galaxy h = 700 LY
Volume of the galaxy = πr²h
= (3.14)(62000)²(700)
= (3.14)(62)²(7)(10)⁸
= 84568×10⁸
=
(LY)³
Since galaxy contains number of stars = 1078 billion stars ≈ 
Now volume covered by each star of the galaxy = 
= 
= 7.839 Light Years
Now the linear dimension across the volume
= 
= 
= 1.99 LY
≈ 2 Light Years
Therefore, approximate linear dimension is 2 light years.
Answer:
66.35m/s
Explanation:
Para resolver el ejercicio es necesario la aplicación de las ecuaciones de continuidad, que expresan que

From our given data we can lower than:


So using the continuity equation we have




Therefore the velocity at the exit end is 66.35m/s
Answer:
please write the question by our way which we can understand