V=4.8 L
c=5.0 mol/L
M(Mg)=24.3 g/mol
1) n(HCl)=cv
2) m(Mg)=M(Mg)n(HCl)/2
3) m(Mg)=M(Mg)cv/2
m(Mg)=24.3*5*4.8/2=291.6 g
Assuming that the number of mols are constant for both conditions:

Now you plug in the given values. V_1 is the unknown.

Separate V_1

V= 162.782608696 L
There are 2 sig figs
V= 160 L
The answer is C.) Pair it with a hydrogen half-cell
Multiply the weight of the object by the distance it traveled to find the amount of work output. For the example: 10 lbs. x 1 foot = 10 foot-pounds. Find the work efficiency by dividing the work output by the work input and multiplying by 100.