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vazorg [7]
3 years ago
6

A Review Constants Periodic Table

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer:

C. 1, 4–dimethyl–1–cyclohexene

D. 4, 6–dichloro–1–heptene

Explanation:

C. Determination of the name of the compound.

To name the compound given above we must observe the following:

1. Determine the functional group of the compound. In this case, the functional group is the double bond (–C=C–).

2. Determine the parent name by counting the number of carbon that makes up the ring. In this case, 6 carbon makes up the ring. Hence the parent name is cyclohexene.

3. Identify the substituent group attached to the compound. In this case, two methyl group i.e –CH₃ are attached.

4. Locate the position of the substituent group attached by giving the functional group the lowest possible count. In this case, the functional group is at carbon 1, the first methyl group is at carbon 1 and the 2nd methyl group is at carbon 4.

5. Combine the above to obtain the name. Thus, the name of the compound is:

1, 4–dimethyl–1–cyclohexene.

D. Determination of the name of the compound.

To name the compound given above we must observe the following:

1. Determine the functional group of the compound. In this case, the functional group is the double bond (–C=C–).

2. Determine the parent name by counting the number of carbon that makes up the chain. In this case, 7 carbons makes up the chain. Hence, the parent name of the compound is heptene.

3. Identify the substituent group attached to the compound. In this case, two chlorine (Chloro) i.e –Cl are attached.

4. Locate the position of the substituent group attached by giving the functional group the lowest possible count. In this case, the functional group is at carbon 1, the first chlorine is at carbon 4 and the 2nd is at carbon 6.

5. Combine the above to obtain the name. Thus, the name of the compound is:

4, 6–dichloro–1–heptene

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Explanation:

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The product of the nuclear reaction in which 40Ar is subjected to neutron capture followed by alpha emission is ________. The pr
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Answer:

37S

Explanation:

Radioactivity is the spontaneous emission of particles and / or electromagnetic radiation by unstable atomic nuclei leading to their disintegration.

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In radioactive decay ( natural radioactivity ), a naturally occurring radioactive element like Uranium-238 disintegrates or decays into more stable isotopes with the emission of particles and/or radiation.

23892U = 23490Th + 42He

Artificial transmutation is the collision of two particles where one particle captures the other used to bombard it. There is subsequent production of isotopes similar or different from the bombarded particle. Neutrons, alpha particles ( helium nucleus ), electrons, protons can be used to bombard elements.

147N + 42He = 178O + 11P

For the above question which is artificial transmutation, the reaction equation is

4018Ar + 10n = 3716S + 42He

So, the neutron capture by Argon-40 will produce a radioisotope Sulphur-37 with the emission of an alpha particle.

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3 years ago
identify each material as a compound or a mixture. Caffeine contains hydrogen, carbon, nitrogen, and oxygen atoms in a fixed rat
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1) As stated c<span>affeine contains hydrogen, carbon, nitrogen, and oxygen atoms in a fixed ratio.

2) The definition of compound is a pure substance formed by chemical bonding of two or more fifferent elements. That means a defined ratio of the elements in the compound, which conferes uniform and equal properties to every part of the compound.

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What is the percent composition of dinotrogen pentoxide? With work shown please
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Answer:

%N = 25.94%

%O = 74.06%

Explanation:

Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅

We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.

m(N): 2 × 14.01 g = 28.02 g

Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅

We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.

m(O): 5 × 16.00 g = 80.00 g

Step 3: Calculate the mass of 1 mole of N₂O₅

We will sum the masses of N and O.

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Step 4: Calculate the percent composition  of N₂O₅

We will use the following expression.

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