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Dominik [7]
3 years ago
7

PLEASE HELP ME ANSWER DUE SOON BRAINLIEST FOR WHOEVER

Physics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

1) mechanical

2) transverse

3) medium

4) longitudinal

Explanation:

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What happens to parallel light rays that strike a concave lens?
torisob [31]

Answer:

They diverge on refraction

Explanation:

When parallel light rays strike a concave lens, they will diverge that is they spread out .

Concave lens is also known as diverging lens, which means that when parallel rays of light strike on it, the lens spreads out the light rays ( that is it diverges the rays of light) that are refracted through it.

At the middle  of concave lens is thinner.  

When light is passes through the lens they diverge it or spread out.

The concave lens causes light rays to bend away or diverge from its axis since the concave lens is a diverging lens.  

5 0
3 years ago
An electric heater is operated by applying a potential difference of 78.0 V across a nichrome wire of total resistance 7.00 Ω. a
aleksley [76]

PART A)

Here we know that

potential difference across the wire is

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resistance of wire is

R = 7 ohm

now by ohm's law

V = iR

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i = 11.14 A

Part b)

Power rating is defined as rate of electrical energy

it is defined as

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P = 869.1 Watt

8 0
3 years ago
1) What are the parts of a longitudinal wave? How are they different?<br> ***
Kay [80]

Answer:

Compression- pushing together

Refraction- pulling apart

Wavelength- the length of the wave

Explanation:

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3 0
3 years ago
Problem 5 You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this gam
Dvinal [7]

Answer:

Option D: 1.5in in front of the target

Explanation:

The object distance is y= 6in.

Because the surface is flat, the radius of curvature is infinity .

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The single interface equation is \frac{n_i}{y}+\frac{n_t}{y^i}=\frac{n_t-n_i}{r}

Substituting the quantities given in the problem,

\frac{\frac{4}{3}}{6in}+\frac{1}{y^i}= 0

The image distance is then y^i=-\frac{18}{4}in =-4.5in

Therefore, the coin falls 1.5in in front of the target

6 0
3 years ago
Is work being done on a barbell when a weight lifter is holding the barbell<br> over his head?
Artemon [7]

Answer:

Because in order for work to be done on an object, the object must be moving. Why isn't work being done on a barbell when a weight lifter is holding the barbell over his head? Work is maximized when force is applied in the same direction that the object is moving. ... In order to do work faster, more_is required.

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