The net force on a rock is 250 newtons downward. The rock accelerates at a rate of 10 m/s2. What is the rock's mass?

If you decrease the distance between successive crests of a wave, this changes

AlexFokin [52]

<span>The _______ is the the distance between two crests or two troughs on a transverse wave. It is also the distance between compressions or the distance between rarefactions on a longitudinal wave.</span>

3 0

3 years ago

The spectrum produced by a prism or a raindrop is evidence that the average speed of light in the material depends on the light'

Alja [10]

The correct answer for the question that is being presented above is this one: "B. color." The spectrum produced by a prism or a raindrop is evidence that the average speed of light in the material depends on the light's color. White light is being refracted into different colors.

4 0

3 years ago

A car has a mass of 975 kg. by pushing on the car, evan increses its speed from 0.5 m/s to 3 m/s. what impulse did evan apply to

jarptica [38.1K]

Impulse = change in momentum = F x dt
Where F is sufficiently large and dt is very small(tending to zero).

Therefore impulse = mass x final velocity - mass x initial velocity
= 975 x 3 - 975 x 0.5
= 2437.5 Kg-m/s.
Hence option C is correct.

7 0

3 years ago

Read 2 more answers

A 0.412 kg metal cylinder is placed inside the top of a plastic tube, the lower end of which is sealed off by an adjustable plun

AveGali [126]

Answer:

108.18 m/s2

Explanation:

1 atm = 101325 Pa

r = 7.41 mm = 0.00741m

Since the pressure is increased by a factor of 2.55, the new inner pressure inside the system would be

P = 101325 * 2.55 = 258378.75 Pa

This pressure exerts a force on the metal cylinder, knowing the radius, we can calculate the cross-section area:

$A = \pi r^2 = \pi 0.00741^2 = 0.0001725 m^2$

Then the force exerted:

$F = A*P = 0.0001725*258378.75 = 44.57 N$

Finally we can calculate the initial acceleration in accordance with Newton's 2nd law of motion:

$a = F/m = 44.57 / 0.412 = 108.18 m/s^2$

7 0

3 years ago

Dock jumping In the sport of dock jumping, dogs run at full speed off the end of a dock that sits a few feet above a pool of wat

melamori03 [73]

To develop this problem we will use the linear motion kinematic equations. To find the time, we will use the information given on the y axis, which will allow us to find the time it takes to complete the route. With this time and the speed given in the horizontal direction, we can calculate the total distance traveled in that direction. Consider the motion of dog along the Y-direction

$V_{0y} = \text{Initial velocity} = 0 m/s$