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Answer:
1.25 m
Explanation:
From the question given above, the following data were obtained:
Force ratio = 2.5
Distance of load from the fulcrum = 0.5 m
Distance of effort =.?
The distance of the effort from the fulcrum can be obtained as illustrated below:
Force ratio = Distance of effort / Distance of load
2.5 = Distance of effort / 0.5
Cross multiply
Distance of effort = 2.5 × 0.5
Distance of effort = 1.25 m
Therefore, the distance of the effort from the fulcrum is 1.25 m
Answer:
t = 2 hours
Explanation:
Given that,
Distance of the town, d = 90 miles
Speed, v = 45 mph
We need to find the time to get there. The speed of an object is given by :
![v=\dfrac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bd%7D%7Bt%7D)
Where
t is time
![t=\dfrac{d}{v}\\\\t=\dfrac{90}{45}\\\\t=2\ h](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7Bd%7D%7Bv%7D%5C%5C%5C%5Ct%3D%5Cdfrac%7B90%7D%7B45%7D%5C%5C%5C%5Ct%3D2%5C%20h)
So, the required time is 2 hours.
Answer:
The difference is 7.6 grams.
Explanation:
In mathematics the difference of two numbers is express as the subtraction between them:
![a-b](https://tex.z-dn.net/?f=a-b)
So to find out the difference between the two measured masses, a will be represented by 123.6 grams since is the bigger number, and b by 115.972 grams.
Therefore, it is get:
![123.6grams-115.972grams = 7.6grams](https://tex.z-dn.net/?f=123.6grams-115.972grams%20%3D%207.6grams)
<u>Hence, the difference is 7.6 grams. </u>
The result of 7.628 will be expressed as 7.6 to have the correct number of significant figures.
Notice how that can be express in units of kilograms too since there is 1000 gram in 1 kilogram:
⇒ ![7.6x10^{-3}Kg](https://tex.z-dn.net/?f=7.6x10%5E%7B-3%7DKg)
Answer:
transmit energy
Explanation:
hope this helps u stay safe